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Sergio039 [100]
3 years ago
6

Sulfur trioxide decomposes to form sulfur dioxide and oxygen, like this: SO3(g)-------SO2(g) + O2(g) Write the pressure equilibr

ium constant expression for this reaction.
Chemistry
1 answer:
Paul [167]3 years ago
8 0

Answer:

Kp = P(SO2)  *   P(O2)  / P(SO3)

Explanation:

The equation is given as;

SO3(g)  --> SO2(g) + O2(g)

In the pressurer equilibrium constant expression, only the gaseous entities are considered.

It is given as;

Kp = P(products)   /  P(reactants)

Product are  SO2(g) and O2(g)

Reactant is SO3(g)

Kp = P(SO2)  *   P(O2)  / P(SO3)

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Given that the molar mass of NaCl is 58.44 g/mol, Solve for the molarity of a solution that contains 87.75 g of NaCl in 500 mL o
aliina [53]

Molarity is defined as the number of moles of solute per 1 L of solvent.

the mass of NaCl in the solution is 87.75 g

number of moles of NaCl is calculated by dividing mass present by molar mass

number of NaCl moles = 87.75 g / 58.44 g/mol = 1.502 mol

the number of NaCl moles in 500 mL is - 1.502 mol

therefore number of NaCl moles in 1000 mL is - 1.502 mol/ 500 mL x 1000 mL/L = 3.004 mol

molarity of NaCl is - 3.004 M

answer is D. 3.00 M

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2. What mass of sodium chloride is produced when chlorine gas reacts with 2.29 grams of sodium iodide? The unbalanced equation i
Damm [24]

Answer:

0.88g

Explanation:

The reaction equation:

         2NaI  + Cl₂   →    2NaCl  + I₂

Given parameters:

Mass of Sodium iodide = 2.29g

Unknown:

Mass of NaCl = ?

Solution:

To solve this problem, we work from the known to the unknown.

First find the number of NaI from the mass given;

   Number of moles  = \frac{mass}{molar mass}  

          Molar mass of NaI  = 23 + 126.9  = 149.9g/mol

 Now insert the parameters and solve;

     Number of moles  = \frac{2.29}{149.9}   = 0.015mol

So;

 From the balanced reaction equation;

            2 moles of NaI produced 2 moles of NaCl

          0.015mole of NaI will produce 0.015mole of NaCl

Therefore;

      Mass  = number of moles x molar mass

      Molar mass of NaCl = 23 + 35.5  = 58.5g/mol

Now;

      Mass of NaCl  = 0.015 x 58.5  = 0.88g

8 0
3 years ago
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