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goldenfox [79]
3 years ago
6

Hang two sheets of paper vertically from adjacent corners. The sheets should be parallel and close to each other with a small ga

p between them. Now gently blow down between the two sheets. What happens? a. The sheets move toward each other and the gap narrows. b. The sheets move away from each other and the gap widens c. Nothing happens. The gap between the two sheets remains constant.
Physics
1 answer:
Mrrafil [7]3 years ago
4 0

Answer:

a. The sheets move toward each other and the gap narrows.

Explanation:

This exercise is related to fluid mechanics, when blowing between the two sheets, we can apply Bernoulli's equation, where the index 2 is the space between the two sheets

       P₁ + ½ ρ g v₁² + ρ g y₁ = P₂ + ½ ρ g v₂² + ρ g y²

if the two leaves are at the same height

                      y₁ = y₂

 whereby

         P₁ + ½ ρ g v₁² = P₂ + ½ ρ v₂²

for the air velocity between the leaves let us use the continuity equation

        A₁ v₁ = A₂ v₂

the area between the leaves is less than the external area, so the air speed must increase. If we use this in Bernoulli's equation, increasing the speed 2 (between the leaves) to maintain equality the pressure must decrease.

If the pressure decreases, the blades should move closer

When resisting the answers, the correct one is  a

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A solid cylinder is released from the top of an inclined plane of height 0.81 m. From what height, in meters, on the incline sho
Jlenok [28]

Answer:

same 0.81m

Explanation:

in this problem if we assume there no resistance of any sort. and we apply the energy conservation

change in Potential energy = change in kinetic energy

mgh = 0.5mv^2

gh = 0.5v^2

the above relation suggests that the speed at the bottom is only depending on the height it is released from not on the shape, mass or radius.

so at the bottom

put h = 0.81m

9.81 * 0.81 * 2 = v^2

v=3.99 m/s

both CYLINDER and SPHERE will have same velocity at the bottom if released from the same height irrespective of shape and size

3 0
3 years ago
A 70.0 kg ice hockey goalie, originally at rest, has a 0.110 kg hockey puck slapped at him at a velocity of 31.5 m/s. Suppose th
NISA [10]

Answer

given,

mass of the goalie(m₁) = 70 kg

mass of the puck (m₂)= 0.11 kg

velocity of the puck = 31.5 m/s

elastic collision

v_1=\dfrac{m_2-m_1}{m_1+m_2}v_1+\dfrac{2m_2}{m_1+m_2}v_2

v_{pf}=\dfrac{0.11-70}{0.11+70}31.5+\dfrac{2m_2}{m_1+m_2}\times (0)

v_{pf}=-31.4\ m/s

v'_2 = \dfrac{2m_1v_1}{m_1+m_2}-\dfrac{(m_2-m_1)v_2}{m_2+m_1}

v_{gf} = \dfrac{2\times 0.11\times 31.5}{0.11+70}-\dfrac{(0.11-70)\times 0}{m_1+m_2}

v_{gf} = \dfrac{2\times 0.11\times 31.5}{0.11+70}

v_{gf} = 0.0988\ m/s

4 0
3 years ago
A. 36 mins 52.5 secs<br> b. 24mins 22.5 secs<br> c. 13 mins 0 secs<br> d. 9 mins 45 secs
DedPeter [7]
I think it might be A. I’m sorry if I’m wrong
5 0
3 years ago
Read 2 more answers
How do galaxies vary?
givi [52]

The universe has trillions of galaxies and counting. Astronomers give names to each galaxy base on its shape (e.i, Sombrero galaxy, Milkyway Galazy, ect,.).

Also, the size of the galaxy is taken into account and their color.


4 0
3 years ago
PLEASE HELP, LOOK AT PHOTO PLZ!!!
PIT_PIT [208]

Answer:

a) 17 km

b) 9 km

Explanation:

The distance is the length of the path.

A to C: 5 km

B to C: 4 km

C to B: 4 km

B to C: 4 km

Total distance = 5 km + 4 km + 4 km + 4 km = 17 km

Displacement is the difference between the starting point and ending point.

Displacement = 9 km − 0 km = 9 km

3 0
3 years ago
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