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goldenfox [79]
3 years ago
6

Hang two sheets of paper vertically from adjacent corners. The sheets should be parallel and close to each other with a small ga

p between them. Now gently blow down between the two sheets. What happens? a. The sheets move toward each other and the gap narrows. b. The sheets move away from each other and the gap widens c. Nothing happens. The gap between the two sheets remains constant.
Physics
1 answer:
Mrrafil [7]3 years ago
4 0

Answer:

a. The sheets move toward each other and the gap narrows.

Explanation:

This exercise is related to fluid mechanics, when blowing between the two sheets, we can apply Bernoulli's equation, where the index 2 is the space between the two sheets

       P₁ + ½ ρ g v₁² + ρ g y₁ = P₂ + ½ ρ g v₂² + ρ g y²

if the two leaves are at the same height

                      y₁ = y₂

 whereby

         P₁ + ½ ρ g v₁² = P₂ + ½ ρ v₂²

for the air velocity between the leaves let us use the continuity equation

        A₁ v₁ = A₂ v₂

the area between the leaves is less than the external area, so the air speed must increase. If we use this in Bernoulli's equation, increasing the speed 2 (between the leaves) to maintain equality the pressure must decrease.

If the pressure decreases, the blades should move closer

When resisting the answers, the correct one is  a

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The liquid pressure varies with depth because liquid pressure is directly proportional to the depth of liquid from the free surface of the liquid. so, more the depth more the pressure and less the depth less the pressure.

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The object has a redshift of 7.6 and the JWST observes the object at a wavelength of 2 microme-
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b. The wavelength of light emitted by the object is 233 nm

c. The type of radiation originally emitted by the object is ultraviolet radiation.

To find the wavelength, we need to know what redshift is.

<h3>What is redshift?</h3>

Redshift is the increase in wavelength and the corresponding decrease of frequency and photon energy of electromagnetic radiation.

Redshift is given by z = λ'/λ - 1 where

  • λ' = observed wavelength and
  • λ = emitted wavelength.

Making λ subject of the formula, we have

λ = λ'/(1 + z)

Given that has a redshift of 7.6 and the JWST observes the object at a wavelength of 2 micrometres (mid-infrared light).

So,

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  • λ' = 2μm

<h3>(b) What is the wavelength of the light emitted by the object?</h3>

Substituting the values of the variables into the equation, we have

λ = λ'/(1 + z)

λ = 2μm/(1 + 7.6)

λ = 2μm/8.6

λ = 0.233 μm

λ = 233 nm

So, the wavelength of light emitted by the object is 233 nm

<h3>c. What type of radiation was originally emitted by the object?</h3>

Since the wavelength is 233 nm and the wavelength is in the range of ultraviolet radiation 200 nm - 315 nm.

So, the type of radiation originally emitted by the object is ultraviolet radiation.

Learn more about redshift here:

brainly.com/question/27915180

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Answer:

Average speed = 24 km/h

Explanation:

  • Let the distance be x.

<u>Given the following data;</u>

Uniform speed A = 30 km/h

Uniform speed B = 20 km/h

To find the average speed;

Mathematically, the average speed of an object is given by the formula;

Average \; speed = \frac {total \; distance}{total \; time} ..... equation 1

Total time = TA + TB

T_{A} = \frac {x}{30}

T_{B} = \frac {x}{20}

Total \; time = \frac {x}{30} + \frac {x}{20}

Total \; time = \frac {5x}{60}

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Total distance = 2x

Substituting the values into equation 1;

Average \; speed = \frac {2x}{\frac {5x}{60}}

Average \; speed = \frac {2x*60}{5x}

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Answer:

1.2 miles

Explanation:

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