A cylinder with a radius of 1.8 cm is floating in water as shown below. The mass of the cylinder is 1.80 kg. Calculate the depth
1 answer:
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Answer:
Theta1 = 12° and theta2 = 168°
The solution procedure can be found in the attachment below.
Explanation:
The Range is the horizontal distance traveled by a projectile. This diatance is given mathematically by Vo cos(theta) t. Where t is the total time of flight of the projectile in air. It is the time taken for the projectile to go from starting point to finish point. This solution assumes the projectile finishes uts motion on the same horizontal level as the starting point and as a result the vertical displacement is zero (no change in height).
In the solution as can be found below, the expression to calculate the range for any launch angle theta was first derived and then the required angles calculated from the equation by substituting the values of the the given quantities.
Answer:
Explanation:
From the question we are told that
Mass of pitcher
Force on pitcher
Distance traveled
Coefficient of friction
a)Generally frictional force is mathematically given by
Generally work done on the pitcher is mathematically given as
b)Generally K.E can be given mathematically as
Therefore
c)Generally the equation for kinetic energy is mathematically represented by
Velocity as subject