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Snezhnost [94]
2 years ago
5

A cylinder with a radius of 1.8 cm is floating in water as shown below. The mass of the cylinder is 1.80 kg. Calculate the depth

of the bottom end of the cylinder
Physics
1 answer:
Westkost [7]2 years ago
6 0

Answer:

Explanation:

I will ASSUME that the cylinder floats with the axis through the center of its flat ends is perpendicular to the water surface.

The cylinder will displace it's mass in water.

water density has a value of 1000 kg/m³

if the depth of the bottom is "h" in meters

1.80 kg = π(0.018² m²)(h m)(1000) kg/m³

h = 1.768388256...

or about 1.77 m

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Explanation:

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two identical springs of spring constant 7580 N/m are attached to a block of mass 0.245 kg. What is the frequency of oscillation
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The frequency of oscillation on the frictionless floor is 28 Hz.

<h3>Frequency of the simple harmonic motion</h3>

The frequency of the oscillation is calculated as follows;

f = (1/2π)(√k/m)

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Learn more about frequency here: brainly.com/question/10728818

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The mass of block B is twice the mass of block A, while the mass of the pulley is equal to the mass of block A. The blocks are l
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Answer:

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Explanation:

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