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Anni [7]
3 years ago
8

48. About 0.01% of men with no known risk behavior are infected with HIV. The false negative rate for the standard HIV test 0.01

% and the false positive rate is also 0.01%. If a randomly selected man with no known risk behavior tests positive for HIV, what is the probability that he is actually infected with HIV
Mathematics
1 answer:
babymother [125]3 years ago
5 0

Answer:

The probability that he is actually infected with HIV given that the man selected with no known risk behavior tests positive for HIV is 0.9999.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a man with no known risk behavior is infected with HIV

<em>Y</em> = the test is positive

The information provided is:

P (X) = 0.0001

P (Y'|X) = 0.0001

P (Y'|X') = 0.0001

Compute the probability that he is actually infected with HIV given that the man selected with no known risk behavior tests positive for HIV as follows:

P(Y|X) = 1-P(Y'|X)\\=1-0.0001\\=0.9999

Thus, the probability that he is actually infected with HIV given that the man selected with no known risk behavior tests positive for HIV is 0.9999.

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7. In a state lottery, a player must choose 8 of the numbers from 1 to 40. The lottery commission then performs an experiment th
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Answer:a) P(8 of the players numbers are drawn)=1.3×10^-8

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Step-by-step explanation:

Players has 8 combinations of numbers from 1-40. The outcome S contains all the combinations of 8 out of 40

a) P(8 of the players numbers are drawn)= 1/40/8= 1.3×10^-8

There are one in hundred million chances that the draw numbers are precisely the chosen ones.

b) Number of ways of drawing 78 selected numbers from 1-40=8×(40-7)

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P(7 of the players number are drawn)=8×32/40 =3.33×10^-6.

There are approximately 300,000 chances that 7 of the players numbers are chosen

c) P(at least 6 players numbers are drawn)= 32/2×(8/6) ways to draw.

P(at least 6 players numbers are drawn)=P(all 8 chosen are drawn)+P(7 players numbers drawn)+P(6 chosen are drawn) = 1+ 8 x32/40/8 +[8\6 ×32/2]

P(at least 6 players numbers are drawn) = 1.84×10^-4.

There are approximately 5400chances that at least6 of the numbers drawn are chosen by the player.

5 0
3 years ago
(34 - 6) =(24-1) is...?
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Answer:

34-6 and 24-1 are not equal to each other

Step-by-step explanation:

(34-6)=(24-1)

28 is not equal to 23

4 0
3 years ago
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