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Aneli [31]
3 years ago
8

The minimum amount of energy that has to be added to start a reaction is the ______________ energy.

Physics
1 answer:
frosja888 [35]3 years ago
7 0
The best and most correct answer among the choices provided by your question is the first choice or letter A.

<span>The minimum amount of energy that has to be added to start a reaction is the activation energy.</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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As part of an interview for a summer job with the Coast Guard, you are asked to help determine the search area for two sunken sh
MrMuchimi

Answer:37^{\circ} North of west

Explanation:

Given

40,000-ton luxury line traveling 20 knots towards west and

60,000 ton freighter traveling towards North with 10 knots

suppose v is the common velocity after collision

conserving momentum in west direction

20\times 40,000=(20,000+60,000)v\cos \theta

suppose the final velocity makes \theta angle with x axis

v\cos \theta =10----1

Conserving Momentum in North direction

10\times 60,000=80,000\times v\sin\theta

v\sin \theta =\frac{15}{2}----2

divide 1 and 2

\tan \theta =\frac{3}{4}

\theta =37^{\circ}

so search in the area 37^{\circ} North of west to find the ship

3 0
3 years ago
A particular light source gives off light waves with a measured wavelength of
Umnica [9.8K]

The frequency of the light source is 1.5 x 10¹⁵ Hz.

<h3>Frequency of the light source</h3>

The frequency of the light source is determined using the following equations;

c = fλ

where;

c is speed of light

f is the frequency

λ is the wavelength

f = (3 x 10⁸) / (2 x 10⁻⁷)

f = 1.5 x 10¹⁵ Hz

Thus, the frequency of the light source is 1.5 x 10¹⁵ Hz.

Learn more about frequency of light here: brainly.com/question/10728818

3 0
2 years ago
a street light is mounted at the top of a 15 foot pole. A man 6 ft tall walks away from the pole wit a speed of 7 ft/s along a s
Mariulka [41]

Answer:

16.3 ft/s

Explanation:

Let d=distance

and

x = length of shadow.

Therfore,

x=(d + x)

 = 6/15

So,

    15x = 6x + 6d

     9x = 6d.

x = (2/3)d.

As we know that:

dx=dt

   = (2/3) (d/dt) 

Also,

Given:

d(d)=dt

     = 7 ft/s

Thus,

d(d + x)=dt

           = (7/3)d (d/dt)

Substitute, d= 7  

d(d + x) = 49/3 ft/s.

Hence,

d(d + x) = 16.3 ft/s.

4 0
3 years ago
A truck with 0.410 m radius tires travels at 25.0 m/s. What is the angular velocity of the rotating tires in radians per second?
Eduardwww [97]

relation between linear velocity and angular velocity is given as

v = R\omega

here

v = linear speed

R = radius

\omega = angular speed

now plug in all data in the equation

25.0 = 0.410 \omega

\omega  = \frac{25}{0.410}

\omega = 60.9 rad/s

so rotating speed is 60.9 rad/s

6 0
2 years ago
A force of 35 N acts on a ball for 0.2 s. If the ball is initially at rest:
olya-2409 [2.1K]

To solve this problem we will apply the concepts related to momentum and momentum on a body. Both are equivalent values but can be found through different expressions. The impulse is the product of the Force for time while the momentum is the product between the mass and the velocity. The result of these operations yields equivalent units.

PART A ) The Impulse  can be calculcated as follows

L= F\Delta t

Where,

F = Force

\Delta t =Change in time

Replacing,

L = (35N)(0.2s)

L= 7N\cdot s

PART B) At the same time the momentum follows the conservation of momentum where:

Initial momentum= Final momentum

And the change in momentum is equal to the Impulse, then

\Delta p = L

And

\Delta p = p_f - p_i

There is not initial momentum then

\Delta p = p_f

L = p_f

p_f = 7N\cdot s = 7kg\cdot m/s

8 0
3 years ago
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