Gravity is when this can float but nebula is not
<h2>Final velocity of man is -0.23 m/s.</h2>
Explanation:
Conservation of linear momentum :
When no external force acts on a system of several interacting particles, the total linear momentum of system is conserved.
Before the Throw ; Man mass (M₁) = 84.1 kg,
Velocity of Man (u₁) = 0 m/s
Book Mass(M₂) = 1.80 kg
Velocity of book (u₂)= 0 m/s
After the throw ; Man mass(M₁) = 84.1 kg
Velocity of Man(V₁) = ?
Book mass(M₂) = 1.80 kg
velocity of book(V₂) = 11.1 m/s
According to conservation of linear Momentum
Initial Momentum = Final Momentum
M₁u₁ +M₂u₂ = M₁v₁ + M₂v₂
84.1 x0 + 1.80 x0 = 84.1 x v₁ + 1.80 x 11.1
0 = 84.1 v₁ + 19.98
v₁ = -19.98 /84.1
= -0.23 m/s
final velocity of man is -0.23 m/s
Answer:
The tension in the string is equal to Ct
And the time t0 when the rension in the string is 27N is 3.6s.
Explanation:
An approach to solving this problem jnvolves looking at the whole system as one body by drawing an imaginary box around both bodies and taking summation of the forces. This gives F2 - F1 = Ct. This is only possible assuming the string is massless and does not stretch, that way transmitting the force applied across it undiminished.
So T = Ct
When T = 27N then t = T/C = 27/7.5 = 3.6s
Answer:
why don't you just look on Google
Explanation:
just search it up on Google lol
Answer:
v=0.5m/s
Explanation:
Given a raft of 180kg, and two simmers of 50kg and 80kg:
The two rafts have an initial velocity of zero:
Hence, the raft starts moving with avelocity of 0.5m/s
-The raft will continue moving in the direction it was initially moving. The raft has a larger mass than the combined mass of the two swimmers, by law of momentum conservation, it's change in velocity will be negligible.
