When light is incident parallel to the principal axis and then strikes a lens, the light will refract through the focal point on the opposite side of the lens.
To find the answer, we have to know about the rules followed by drawing ray-diagram.
<h3>What are the rules obeyed by light rays?</h3>
- If the incident ray is parallel to the principal axis, the refracted ray will pass through the opposite side's focus.
- The refracted ray becomes parallel to the major axis if the incident ray passes through the focus.
- The refracted ray follows the same path if the incident light passes through the center of the curve.
Thus, we can conclude that, when light is incident parallel to the principal axis and then strikes a lens, the light will refract through the focal point on the opposite side of the lens.
Learn more about refraction by a lens here:
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The answer is kinetic energy
Explation: it is moving
Answer:
F = 2325 N
Explanation:
given,
mass of the car, m = 1550 Kg
initial speed, u = 10 m/s
final speed, v = 25 m/s
time, t = 10 s
Average net force = ?
acceleration of the car
a = 1.5 m/s²
we know
F = m a
F = 1550 x 1.5
F = 2325 N
Net average force applied on the car is equal to 2325 N.
Its .5m/s cause you divide it
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Answer:
191.316 K or -81.684 °C
Explanation:
From general gas law,
P₁V₁/T₁ = P₂V₂/T₂ ................ Equation 1
Where P₁ = Initial pressure, V₁ = Initial volume, T₁ = Initial temperature, P₂ = Final pressure, V₂ = Final volume, T₂ = Final Temperature.
Make T₂ the subject of the equation.
T₂ = P₂V₂T₁/P₁ V₁ ............... Equation 2
Given: P₁ = 5.00×10⁶ Pa, T₁ = 25.0°C = 298 K, P₂ = 1.07×10⁶.
Let: V₁ = y cm³, V₂ = 3y cm³
Substitute into equation 2,
T₂ = (1.07×10⁶×298×3y)/(5.00×10⁶×y)
T₂ =191.316 K.
Hence the final temperature = 191.316 K or -81.684 °C
