You could use a scale to measure the mass as well as a cup to hold the water. If you were comparing the two, you should also probably use a graduated cylinder to get the same amount of each type of water.
Hope this helped ^_^
Answer:
= 9.28 g CO₂
Explanation:
First write a balanced equation:
CH₄ + 2O₂ -> 2H₂O + CO₂
Convert the information to moles
7.50g CH₄ = 0.46875 mol CH₄
13.5g O₂ = 0.421875 mol O₂
Theoretical molar ratio CH₄:O₂ -> 1:2
Actual ratio is 0.46875 : 0.421875 ≈ 1:1
If all CH₄ is used up, there would need to be more O₂
So O₂ is the limiting reactant and we use this in our equation
Use molar ratio to find moles of CO₂
0.421875 mol O₂ * 1 mol CO₂/2 mol O₂=0.2109375 mol CO₂
Then convert to grams
0.2109375 mol CO₂ = 9.28114 g CO₂
round to 3 sig figs
= 9.28 g CO₂
D.) closeness of a measurement to an accepted value
That is accuracy not precision.
Answer:
<span>Chlorine (Cl) is the oxidizing agent because it gains an electron.
Explanation:
Reaction is as follow,
</span><span> Cl</span>₂<span> (aq) + 2 Br</span>⁻<span> (aq) </span>→ <span> 2Cl(aq) + Br</span>₂ <span>(aq)
Oxidation Reaction:
2 Br</span>⁻ → Br₂ + 2 e⁻
Two atoms of Br⁻ (Bromide) looses two electrons to form Br₂ molecule. Hence it is oxidized and is acting as reducing agent.
Reduction Reaction:
Cl₂ + 2 e⁻ → 2 Cl⁻
One molecule of Cl₂ gains two electrons to form two chloride ions (Cl⁻). Therefore, it is reduced and has oxidized Br⁻, Hence, acting as a oxidizing agent.
