Answer:
a) 2-5 = -3
b) 3(4) + 2(4) = 20
c) (3(5)+2)(5-4) = 17
Step-by-step explanation:
Substitute the variables for their values and then solve from there. Hopefully this helps, I don't know if I answered your question fully.
It’s D bcs it’s D random letters tntntntmgkgnfntktkgkfkt
Answer:
3 student.
Step-by-step explanation:
From the first statement:
Let the total score be T
Let the total number of student be x
The average of the score = 72
Average = Tota score / number of student
72 = T/x
Cross multiply
T = 72x ..... (1)
Second statement:
One more student took the test and the average becomes 76 with the student having a score of 88.
Therefore,
Overall score = T + 88
Total student = x + 1
Average = 76
Average = overall score / total number of student
76 = (T + 88) /(x + 1)
Cross multiply
76(x + 1) = T + 88
Clear bracket
76x + 76 = T + 88
From equation 1
T = 72x
76x + 76 = 72x + 88
Collect like terms
76x – 72x = 88 – 76
4x = 12
Divide both side by the coefficient of x i.e 4
x = 12/4
x = 3
Therefore, the initial number of the student were 3.
Answer:
A piece of carrot cake is $4
Step-by-step explanation:
Set this up as an equation.
Let’s have “c” represent cheese cake
And “p” represent pie.
4c+p=18
7c+3p=34
I would solve this using substitution because you already have one “p” in the top equation.
Subtract the 4c and move it to the other side.
p=18-4c
Now plug the equation above into your other equation
7c+3(18-4c)=34
Distribute the 3 into 18-4c
7c+54-12c=34
Combine like terms.
54-5c=34
Subtract 54 to both sides
-5c=-20
Divide -5 to both sides
C=4
A piece of carrot cake is $4