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Alinara [238K]
3 years ago
7

At 570. mm Hg and 25°C, a gas sample ne (in mm Hg) at a volume of 1250 mL and a temperature of 175°C and 25°C, a gas sample has

a volume of 2270 mL. What is the final pressure
Chemistry
1 answer:
maw [93]3 years ago
5 0

Answer:

final pressure ( P2) = 467.37 mm Hg

Explanation:

ideal gas:

  • PV = nRT

∴ P1 = 570 mm Hg * ( atm / 760 mm Hg ) = 0.75 atm

∴ T1 = 25 ° C = 298 K

∴ V1 = 1.250 L

∴ R = 0.082 atm L / K mol

⇒ n = P1*V1 / R*T1

⇒ n = (( 0.75 ) * ( 1.25 )) / (( 0.082 ) * ( 298 ))

⇒ n = 0.038 mol gas

∴ T2 = 175 °C ( 448 K )

∴ V2 = 2.270 L

⇒ P2 = nRT2 / V2

⇒ P2 = (( 0.038 ) * ( 0.082 ) * ( 448 )) / 2.270

⇒ P2 = 0.615 atm * ( 760 mm Hg / atm ) = 467.37 mm Hg

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garik1379 [7]

Answer:

The choice of the answer is fourth option that is -61 degrees.

Therefore the temperature drop is -61°Centigrade.

Explanation:

Given:

The temperature in a town started out at 55 degrees

Start temperature = 55°Centigrade. (Initial temperature)

End of the Day      = -6°Centigrade. (Final temperature)

To Find:

How far did the temperature drop?

Solution:

We will have,

\textrm{Temperature drop}=\textrm{Final temperature}-\textrm{Initial temperature}

Substituting the above values in it we get

\textrm{Temperature drop}=-6-55\\\\\therefore \textrm{Temperature drop}=-61\° centigrade

Therefore the temperature drop is -61°Centigrade.

4 0
3 years ago
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Troyanec [42]

Answer: I think the answer is 1

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Explanation:

5 0
3 years ago
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Ethanol has a density of 0.789 g/cm3. What is the mass of 423 cm3 of ethanol? M = (D)(V)
Ivahew [28]

Answer:

<h2>The answer is 334 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume of ethanol = 423 cm³

density = 0.789 g/cm³

So we have

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6 0
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jeka57 [31]
The scientific method                                  


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podryga [215]

Answer:


                  Option-1 (O²⁻) is the correct answer.


Explanation:

                       All given anions contains same charge. So, we can ignore the effect of charge on these anions.


As we know all given compounds belongs to same group (Group 6) in periodic table. And from top to bottom along the group the elements are placed as,


                                                          Oxygen O


                                                          Sulfur S


                                                          Selenium Se


                                                          Tellurium Te


Hence, moving from top to bottom along the group the number of shells increases. And with increase in number of shell the atomic or ionic radii increases. As Oxygen is present at the top of the group, therefore, it has the smallest radius due to less number of shells.

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