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kobusy [5.1K]
3 years ago
9

How can juggling improve your hand eye coordination?​

Physics
2 answers:
Ne4ueva [31]3 years ago
5 0

Answer:

you can predict where the juggling ball is going to land and the move you hand to catch it

Explanation:

kiruha [24]3 years ago
5 0

Answer:

it builds hand-eye coordination in ways that improve reaction time, reflexes, spatial awareness, strategic thinking, and concentration.

Explanation:

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Which is longer, 10 cm or .01 m?
motikmotik

Answer:

They´re the same.

Explanation:

Someone deleted my answer. And my brainly is gone..

Have a good night ma´am/sir.

Be safe!

6 0
3 years ago
Write down the SI unit of length and mass​
Vanyuwa [196]

Answer:

The SI unit for length is meters(m), for mass is kilograms(kg)

Explanation:

hope it helps

6 0
3 years ago
Can someone please answer this question in simple terms and not over complicated. i know nothing about the subject.
Westkost [7]

Answer:

Mix

Explanation:

A battery has two electrodes, at one end it has the anode and the other end has the cathode. Electrons travel through the circuit from the anode (negative) to the cathode (positive), and this is the driving force that provides electricity to flow through circuits.

The anode needs to have a low electron affinity because it needs to readily release electrons, and the cathode needs to have a high electron affinity because it needs to readily accept electrons.

8 0
3 years ago
A barge floating in fresh water (p = 1000 kg/m3) is shaped like a hollow rectangular prism with base area A = 550 m2 and height H
Karolina [17]

Answer:

a) \Delta m = 330000\,kg, b) h = 1.268\,m

Explanation:

a) According the Archimedes' Principle, the buoyancy force is equal to the displaced weight of surrounding liquid. The mass of the coal in the barge is:

\Delta m \cdot g = \rho_{w}\cdot g \cdot \Delta V

\Delta m = \rho_{w}\cdot \Delta V

\Delta m = \left(1000\,\frac{kg}{m^{3}} \right)\cdot (550\,m^{2})\cdot (1.05\,m-0.45\,m)

\Delta m = 330000\,kg

b) The submersion height is found by using the equation derived previously:

\Delta m = \rho_{w}\cdot \Delta V

450000\,kg = \left(1000\,\frac{kg}{m^{3}}\right)\cdot (550\,m^{2})\cdot (h-0.45\,m)

The final submersion height is:

h = 1.268\,m

4 0
3 years ago
Read 2 more answers
(TCO-8) A band-pass filter has fC1 = 5 kHz and fC2 = 88 kHz. Calculate Bandwidth (BW) and center frequency (fo) for this filter.
Temka [501]

Bandwidth is the difference between the upper and lower frequencies in a continuous band of frequencies.

Mathematically can be expressed as,

BW = F_{c2}-F_{c1}

The upper frequency is 88Hz and the lower frequency is 6, therefore the Bandwidth would be,

BW = (88-5)kHz

BW = 83kHz

The center frequency is given on the basis of the square root of the multiplication of the two reference frequencies, then,

f_0 = \sqrt{f_{c1}*f_{c2}}

f_0 = \sqrt{88*5}

f_0 = 20.97kHz

7 0
3 years ago
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