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kobusy [5.1K]
3 years ago
9

How can juggling improve your hand eye coordination?​

Physics
2 answers:
Ne4ueva [31]3 years ago
5 0

Answer:

you can predict where the juggling ball is going to land and the move you hand to catch it

Explanation:

kiruha [24]3 years ago
5 0

Answer:

it builds hand-eye coordination in ways that improve reaction time, reflexes, spatial awareness, strategic thinking, and concentration.

Explanation:

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Love, which can’t be observed or measured directly, is an example of a psychological construct. true or false
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Isn't love a social construct?

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At a certain instant, the speedometer of the car indicates 80 km/h.
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<em>.</em><em> </em>

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{\bold{\red{HOPE\:IT\:HELPS!}}}

\color{yellow}\boxed{\colorbox{black}{MARK\: BRAINLIEST!❤}}

4 0
2 years ago
WILL MARK BRAINLIEST JUST PLEASE HELP
mixer [17]

Answer:

40N in either direction is the answer

6 0
3 years ago
Read 2 more answers
What happens to the electric potential energy of a negatively charged ion as it moves through the water from the negative probe
Nataly [62]

Answer:

Decreases.

Explanation:

Electric potential energy is the potential energy which is associated with the configuration of points charge in a system and it is the result of conservative coulomb force.

When the negatively charge ion is at the position of the negative probe than its potential energy is positive when it is move towards the positive probe it's potential energy becomes negative due to the negative ion.

Therefore, potential energy is decreases when negative charge ion moves through the water from negative probe to positive probe.

5 0
3 years ago
Imagine that the earth and the-moon have positive charges of the same magnitud. How big isäºthe charge necesary to produce an el
lions [1.4K]

Answer:

5.7 x 10^12 C

Explanation:

Let the charge on earth and moon is q.

mass of earth, Me = 5.972 x 10^24 kg

mass of moon, Mm = 7.35 x 10^22 kg

Let d be the distance between earth and moon.

the gravitational force between them is

F_{g}=G\frac{M_{e} \times M_{m}}{d^{2}}

The electrostatic force between them is

F_{e}=\frac{Kq^{2}}{d^{2}}

According to the question

1 % of Fg = Fe

0.01 \times 6.67\times10^{-11}\frac{5.97 \times 10^{24}\times7.35 \times 10^{22}}{d^{2}}=9 \times 10^{9}\frac{q^{2}}{d^{2}}

2.927 \times 10^{35}=9 \times10^{9}q^{2}

3.25 \times 10^{25}=q^{2}

q = 5.7 x 10^12 C

Thus, the charge on earth and the moon is 5.7 x 10^12 C.

6 0
3 years ago
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