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3 years ago

238 U 92 is an isotope notation. what is the atomic number, mass number, number of protons, and number of neutrons?

Chemistry

1 answer:

sergejj [24]3 years ago

5 0

Atomic Number: 92

Mass Number: 238

Number of Protons: 92

Number of Neutrons: 146 (you calculate this by subtracting 238 from 92)

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Once the ionic solid has dissolved, the anion that is formed is able to react as a base, with water as the acid. Write the net a

puteri [66]

Answer:

OCl− + H2O ⇌ HOCl + OH−

Explanation:

Sodium hypochlorite is a corrosive base with pH 13, that will react with water in a neutralization process to finally obtein hypochlorous acid. This acid has a great disinfectant effect in water.

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3 years ago

Assuming that both cases describe hydrogen‑like atoms with one electron, for which case is more energy emitted or absorbed?

Nana76 [90]

Assuming that both cases describe hydrogen‑like atoms with one electron, More energy is emitted or absorbed for case 2. The correct option is D.

<h3>What is emitting of energy, by electron?</h3>

The energy of the electron decreases as it changes levels, and emission of photons happens in the atom.

With the electron moving from a higher to a lower energy level, the photon is emitted. The photon's energy is the same as the energy lost by an electron moving to a lower energy level.

Thus, the correct option is D, More energy is emitted or absorbed for case 2.

Learn more about emitting of energy

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2 years ago

What happens to<br> carbon dioxide?

Molodets [167]

Moves from the atmosphere to the oceans

3 0

2 years ago

Read 2 more answers

A 3.4 g sample of an unknown monoprotic organic acid composed of C,H, and O is burned in air to produce 8.58 grams of carbon dio

Pavlova-9 [17]

Answer:

$C_7H_6O_2$

Explanation:

Hello there!

In this case, we can divide the problem in three stages: (1) determine the empirical formula with the combustion analysis, (2) compute the molar mass of acid via the moles of the acid in the neutralization and (3) determine the molecular formula.

(1) In this case, since 8.58 g of carbon dioxide are released, we can first compute the moles of carbon in the compound:

$n_C=8.58gCO_2*\frac{1molCO_2}{44.01gCO_2}*\frac{1molC}{1molCO_2}=0.195molC$

And the moles of hydrogen due to the produced 1.50 grams of water:

$n_H=1.50gH_2O*\frac{1molH_2O}{18.02gH_2O}*\frac{2molH}{1molH_2O} =0.166molH$

Next, to compute the mass and moles of oxygen, we need to use the initial 3.4 g of the acid:

$m_O=3.4g-0.195molC*\frac{12.01gC}{1molC}-0.166molH*\frac{1.01gH}{1molH} =0.89gO\\\\n_O=0.89gO*\frac{1molO}{16.0gO}=0.0556molO$

Thus, the subscripts in the empirical formula are:

$C=\frac{0.195}{0.0556}=3.5 \\\\H=\frac{0.166}{0.0556}=3\\\\O=\frac{0.0556}{0.0556}=1\\\\C_7H_6O_2$

As they cannot be fractions.

(2) In this case, since the acid is monoprotic, we can compute the moles by multiplying the concentration and volume of KOH:

$n_{KOH}=0.279L*0.1mol/L\\\\n_{KOH}=0.0279mol$

Which are equal to the moles of the acid:

$n_{acid}=0.0279mol$

And the molar mass:

$MM_{acid}=\frac{3.4g}{0.0279mol} =121.86g/mol$

(3) Finally, since the molar mass of the empirical formula is:

7*12.01 + 6*1.01 + 2*16.00 = 122.13 g/mol

Thus, since the ratio of molar masses is 122.86/122.13 = 1, we infer that the empirical formula equals the molecular one:

$C_7H_6O_2$

Best regards!

8 0

3 years ago

how many minutes does it take light from the sun to reach earth the distance from the sun to earth is 93 million mi the speed of

Tems11 [23]

Look to be honest, I don't know how to work out the problem, but my teacher, and my says it takes 8 minutes for the Sun's light to reach

hope my answer works :)

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3 years ago