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3 years ago

True or False: The only planet that has gravity is the Earth.

Chemistry

1 answer:

taurus [48]3 years ago

6 0

Answer:

False.

Explanation:

all planets have gravity because if they didnt, the gasses and whatever makes up the planet wouldnt be pulled down to the core of the planet, and it would just be floating around in space.

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A gas has a volume of 560 mL at a temperature of –55°C. What volume will the gas occupy at

kap26 [50]

Answer: 778 ml

Explanation:

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1\text{ and }T_1$ are the initial volume and temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and temperature of the gas.

We are given:

$V_1=560ml\\T_1=-55^oC=(273-55)K=218K\\V_2=?\\T_2=30.0^oC=(273+30.0)K=303K$

Putting values in above equation, we get:

$\frac{560ml}{218K}=\frac{V_2}{303K}\\\\V_2=778ml$

Thus volume the gas occupy at 30.0°C is 778 ml

7 0

3 years ago

A quantity of CO gas occupies a volume of 0.32 L at 0.90 atm and 323 K . The pressure of the gas is lowered and its temperature

Contact [7]

Mathematical formula of Ideal Gas Law is PV=nRT
where: P-pressure,
V-volume
n-number of moles; m/MW
T-Temperature
m-mass
d-density ; m/V
MW-Molecular Weight
R- Ideal Gas constant. If the units of P,V,n & T are atm, L, mol & K respectively, the value of R is 0.0821 L x atm / K x mol

Substituting the definitions to the original Gas equation becomes:
d= P x MW / (RxT)

Solution : d= .90atm x 28 g/mol (CO) / 0.0821Lxatm / mol x K x 323 K

d = 25.2 g / 26000 mL

d = .0.00096 g/mL is the density of CO under the new conditions

5 0

4 years ago

Given the following values for the change in enthalpy (deltaH) and entropy (deltaS), which of the following processes can occur

Shtirlitz [24]

Answer:

Option A and B

Explanation:

(a) DeltaH = -84 kj mol-2 (-20 kcal mol-1), DeltaS = +125j mol-2K-1)(+30 cal mol-1 K-1)

Delta G = Delta H – T * DS

Substituting the given values, we get –

Delta G = -84 -298 *(125/1000) = -121.25 KJ/mol

Delta G is negative hence the process is spontaneous and will not violate the second law of thermodynamics

(b) DeltaH = -84 kj mol-2 (-20 kcal mol-1), DeltaS = -125j mol-2K-1)(-30 cal mol-1 K-1)

Delta G =-84 -298 *(-125/1000) = -46.75 KJ/mol

Delta G is negative hence the process is spontaneous and will not violate the second law of thermodynamics

Delta G = 84 -298 *(125/1000) = +46.75 KJ/mol

Delta G is positive hence the process is non-spontaneous and will violate the second law of thermodynamics

(d) DeltaH = +84 kj mol-2 (+20 kcal mol-1), DeltaS = +125j mol-2K-1)(-30 cal mol-1 K-1)

Delta G = 84 -298 *(-125/1000) = + 121.25 KJ/mol

Delta G is positive hence the process is non-spontaneous and will violate the second law of thermodynamics

6 0

3 years ago

What has a larger mass, a mole of oxygen gas or a mole of neon gas?

Maksim231197 [3]

Answer:

1 mole ozone gas

Explanation:

Since atomicity of Ozone (3) is maximum so, it will contain maximum number of atoms.

4 0

2 years ago

Explain hydrocarbons as fue

Aloiza [94]

<span>google it and you should have the answer I had the same problem </span>

7 0

3 years ago