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3 years ago

Please answer fast!!!

Physics

2 answers:

sesenic [268]3 years ago

5 0

Answer:1. A chair leaning on a wall

Explanation:

Taya2010 [7]3 years ago

3 0

3 A ball on the grass

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Oxygen gas having a volume of 1010 cm3 at 20.7°C and 1.04 x 105 Pa expands until its volume is 1570 cm3 and its pressure is 1.07

Ksju [112]

Answer:

final temperature is 469.71 K = 196.71 °C

Explanation:

Given data

volume V = 1010 cm3 = 0.00101 m³

temperature = 20.7°C = 20.7 + 273 = 293.7 K

pressure P1 = 1.04 x 10^5 Pa

volume = 1570 cm3

pressure P2 = 1.07 x 10^5 Pa

to find out

number of moles of oxygen and final temperature

solution

we know that for ideal gas

PV = nRT

put here all value to get n

R gas constant = 8.314472 J/mol−K and T = 293.7 K and V = 0.00101 m³

and P = 1.04 x 10^5

so n = ( 1.04 x 10^5 × 0.00101 ) / ( 8.314472 × 293.7 )

n = 0.043015 moles

and

now we use equation

P1V1 /T1 = P2V2 / T2

1.04 x 10^5 × 1010 / 293.7 = 1.07 x 10^5 × 1570 / T2

T2 = 49338663 / 105040 = 469.71 K

so final temperature is 469.71 K = 196.71 °C

4 0

3 years ago

Why are vectors important in physics?

quester [9]

They are quantities with magnitude and direction like velocity, we'd be doomed without them to be honest , just knowing how fast something is going isn't enough, you want to know where it is going

7 0

4 years ago

A 2578-kg van runs into the back of a 825-kg compact car at rest. They move off together at 8.5 m/s. Assuming the friction with

allochka39001 [22]

Answer:

The initial speed of the car = 11.22 m/s

Explanation:

Law of conservation of energy: It states that when two bodied collide in a closed system, the sum of momentum before collision is equal to the sum of momentum after collision.

Note: A close system is one that is free from from external forces. E.g Frictional force.

From the law of conservation of momentum,

Total momentum before collision = Total momentum after collision.

m₁u₁ + m₂u₂ = (m₁ + m₂)V..................... Equation 1

Where m₁ = mass of the van, m₂ = mass of the car, u₁ = initial velocity of the van, u₂ = initial velocity of the car, V = Common velocity.

Given: m₁ = 2578 kg, m₂ = 825 kg, u₂ = 0 ( the car was at rest), V= 8.5 m/s

Substituting these values into equation 1, and solving for u₁

2578(u₁) + (825 × 0) = (2578 + 825)8.5

2578u₁ = 28925.5

Dividing both side of the equation by the coefficient of u₁

2578u₁/2578 = 28925.5/2578

u₁ = 11.22 m/s

The initial speed of the car = 11.22 m/s

3 0

4 years ago

6. For the following graph what can you conclude about the force applied to cause the object’s motion? Explain your reasoning

RSB [31]

Answer:

For each second the position increased by 10 m

3 0

3 years ago

Read 2 more answers

11 Design Imagine that a scientistdiscovered a way to make africtionless surface. What wouldbe some useful applications forthis

m_a_m_a [10]

Answer:

You could move something across the Earth with a little push. It would make fuel really efficient on those pathways. You could make a floor that is impossible to walk on. Everybody would just fall without traction.

Explanation:

3 0

3 years ago