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kaheart [24]
3 years ago
14

Name the principle which states that energy

Physics
2 answers:
saw5 [17]3 years ago
6 0

Answer:

the Laws of Thermodynamics

Explanation:

these laws states that no form of energy can be created by anyone or anything, without a previous and equal input of energy being put in, that energy can only be transferred from object to object and through different forms

Example: the way a heater runs to warm up an area, that is the process of electrical energy, or energy stored in propane being <em>converted </em>into heat energy

this law is universally implied and has been proven on multiple accounts to be true, in no way can you create energy out of thin air, all you can do is transform and transfer it

hope this is what you was going for, very good point in science

this is one of two correct answers, the other answer to this question is also correct

Alenkasestr [34]3 years ago
5 0
Law of Conservation of Energy
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Please only serious answers if you dont know the ansnwer, dont answer
Sedaia [141]

Answer:

Explanation:

A free-body diagram is a sketch of an object of interest with all the surrounding objects stripped away and all of the forces acting on the body shown. The drawing of a free-body diagram is an important step in the solving of mechanics problems since it helps to visualize all the forces acting on a single object. The net external force acting on the object must be obtained in order to apply Newton's Second Law to the motion of the object.

A free-body diagram or isolated-body diagram is useful in problems involving equilibrium of forces.

Free-body diagrams are useful for setting up standard mechanics problems.

8 0
3 years ago
A robin in flight has 20.8 J of PE when it is 27.6 m high. What is the mass of the robin? (Unit = kg)
schepotkina [342]

Answer:

<h2>\boxed{  \bold{ \purple{0.0769 \: kg \: }}}</h2>

Explanation:

\sf{Potential   Energy ( P.E ) \:  =  \: 20.8 \: joule}

\sf{distance \:  = 27.6 \: metre}

\sf{mass = } ?

\sf{acceleration \: due \: to \: gravity = 9.68 \:  {metre \: per \: second}^{2} }

Now, let's find the mass:

\sf{PE  \:  =  mass \times gravity \:  \times  \: distance}

plug the values

⇒\sf{20.8 = m \times 9.8 \times 27.6}

Multiply the numbers

⇒\sf{20.8 = 270.48 \: m}

Swap the sides of the equation

⇒\sf{270.48m = 20.8}

Divide both sides of the equation by 270.48

⇒\sf{ \frac{270.48m}{270.48}  =  \frac{20.8}{270.48} }

Calculate

⇒\sf{0.0769} kg

Hope I helped!

Best regards!!

7 0
3 years ago
Read 2 more answers
The "lead" in pencils is a graphite composition with a Young’s modulus of about 1×1010N/m21×1010⁢N/m2. Calculate the change in l
Tanya [424]

Answer:

b) 0.1 mm

Explanation:

Given that

E= 1 x 10¹⁰ N/m²

F= 4 N

d= 0.5 mm

L = 60 mm

We know that elongation due to force F given as

\Delta L=\dfrac{FL}{AE}

\Delta L=\dfrac{FL}{\dfrac{\pi d^2}{4}\times E}

\Delta L=\dfrac{4\times 60}{\dfrac{\pi \times 0.5^2}{4}\times 10^4}

ΔL = 0.12 mm

Therefore the answer is -

b) 0.1 mm

6 0
3 years ago
Explain the law of conservation of energy. Give a specific example using kinetic and potential energy that shows how energy is c
Ede4ka [16]

Answer:

As you said you already know, energy cannot be created or destroyed.

Explanation:

You cannot gain energy or lose energy, it can only be converted. So if you start on a 3m high hill and go down it, your potential energy is equal to mgh, and if you get to the bottom of the hill, your KE would be equal to your PE at the top, and when you start going up another hill again, the maximum height you can reach is 3m, because energy cannot be created or destroyed, and your mass and gravitational acceleration are the same, so therefore you can only reach the same height you started from due to the conservation of energy.

7 0
3 years ago
A body weighing 250 grams was dropped from a helicopter flying at an altitude of 100 meters. Determine the potential energy of t
kogti [31]

Answer:

the potential energy of this body is 245 J.

Explanation:

Given;

mass of the body, m = 250 g = 0.25 kg

height from which the body was dropped, h = 100 m

acceleration due to gravity, g = 9.8 m/s²

The potential energy of this body is calculated as;

P.E = mgh

substitute the given values and solve for the potential energy of this body;

P.E = 0.25 x 9.8 x 100

P.E = 245 J.

Therefore, the potential energy of this body is 245 J.

7 0
3 years ago
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