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PilotLPTM [1.2K]
3 years ago
14

What do we get from the area between the speed-time graph of a body and the time axis?​

Physics
1 answer:
maxonik [38]3 years ago
7 0

Explanation:

The area between the speed-time graph f a body and time axis measures the distance travelled by the body

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Which of these objects must have the greatest force acting on it? pls help fast
8_murik_8 [283]

Let's look at Newton's second law

  • F=ma

Force is directly proportional towards mass

If mass is more force will be more.

Between baseball and bowling ball Bowling ball has higher mass

So it would expert most force

Option D

8 0
2 years ago
The record height of a man to date is 8 feet 11 inches​ (107 inches). If all men had identical body​ types, their weights would
Alisiya [41]

Answer:

679.08 lbs

Explanation:

Here it is given that

m\propto h^3

m_1 = Mass of first person = 175 pounds

h_1 = Height of first person = 70 inches

m_2 = Mass of second person

h_2 = Height of second person = 110 inches

\frac{m_1}{m_2}=\frac{h_1^3}{h_2^3}\\\Rightarrow m_2=\frac{m_1h_2^3}{h_1^3}\\\Rightarrow m_2=\frac{175\times 110^3}{70^3}\\\Rightarrow m_2=679.08\ lb

The weight of the second person would be 679.08 lbs

5 0
4 years ago
As a stunt for movie two cars are to collide with each other head on. The two cars are initially 125 apart. Car A is heading str
Tema [17]

Answer:

3.39724 seconds

23.0824792352 m, 101.917520765 m

13.58896 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

The equation of motion will be

s=ut+\dfrac{1}{2}at^2\\\Rightarrow 125=30\times t+\dfrac{1}{2}\times 4\times t^2\\\Rightarrow 2t^2+30t-125=0\ m

t=\frac{5\left(\sqrt{19}-3\right)}{2},\:t=-\frac{5\left(3+\sqrt{19}\right)}{2}\\\Rightarrow t=3.39724, -18.39724

The time at which the cars collide is 3.39724 seconds

s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 4\times 3.39724^2\\\Rightarrow s=23.0824792352\ m

Car B traveled 23.0824792352 m and Car A traveled 125-23.0824792352 = 101.917520765 m

v=u+at\\\Rightarrow v=0+4\times 3.39724\\\Rightarrow v=13.58896\ m/s

The speed of car B is 13.58896 m/s

4 0
3 years ago
What are the factor that affect the efficiency of a pulley​
alukav5142 [94]

Answer:

Tension in the chains - In a chain drive, technically, you have a closed-chain (which has no end) going around 2 pulley or gears; looking closely you have 2 parallel chains going in opposite direction. If kept in horizontal direction, the one below the other is the slack side and the other the tight side. The tension on the upper or tight side is more than the slack side. So you need to keep in mind to keep your chain drive tight so that there is no loss or rotation or lags.

Sizes of the pulley/gear - The chain will be warped around a pair of pulley or gear. The sizes of these pulley/gear will also determine the efficiency of the chain drive (consider one big and one small)

Number of pulley/gear - If the number of pulley/gear is more and chain wrapped on it with little complexity will result in decrease in efficiency because of extra tension.

Length of the chain drive - You cannot have much too long chain drive. It will make your slack side more heavy because the end are further away. You have to apply more power and possibilities of lag increases decreasing efficiency. In an ideal situation, this won't happen, but this world isn't ideal.

Friction between chains & pulley/gear - If you have studied gears (involving its teeth), you will come to know that there is friction offered on the two meeting surfaces.

Angle of contact - This would have been explained better with a diagram. Although, if you are familiar with the terms you won't have difficulty understanding. Angle of contact is the angle the chain forms with the pulley/gear at the point of contact with the center of the pulley. The angle of contact should not be too small, or else the things will be slippery.

Explanation:

8 0
4 years ago
PLEAAASEE HELLPPPP?!?!?!
vfiekz [6]

Answer:

water evaporates into the atmosphere

8 0
3 years ago
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