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3 years ago

If two organisms evolve in response to each other, which evolutionary pattern is demonstrated

Physics

2 answers:

Taya2010 [7]3 years ago

6 0

Something super duper uper stuper luper nuper tuper zuper yuper fuper guper huper kuper juper wuper special

MissTica3 years ago

3 0

Emigration hopefully this helps ..

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what are 3 CHEMICAL REACTIONS that you personally observed over the last 2 weeks. You should only include chemical reactions tha

Allisa [31]

1). I started up my car. Gasoline was spritzed into the cylinders, mixed with air, and then exploded with an electrical spark. As the gasoline vapor instantly burned in the air, several new things were formed that weren't there before, like carbon dioxide, carbon monoxide, water, and oxides of nitrogen.

2). I left my dinner on the stove a little too long, and it got a layer of crunchy crackly sooty carbon on the bottom. That part of it didn't taste too good. This isn't exactly something that happens every day, but more often than I'd like it too.

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3 years ago

Metamorphic rock is not formed from

Mashcka [7]

Metamorphic rock is not formed from A. erosion

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3 years ago

Read 2 more answers

The speed of a tennis ball that is served is 73.14 m/s. During a serve, the ball typically starts from rest and is in contact wi

Serga [27]

Answer: Third option

F = 250w

Explanation:

The impulse can be written as the product of force for the time interval in which it is applied.

$I = F (t_2-t_1)$

You can also write impulse I as the change of the linear momentum of the ball

$I = mv_2 -mv_1$

So:

$F (t_2-t_1) = mv_2 -mv_1$

We want to find the force applied to the ball. We know that

$(t_2-t_1) = 30$ milliseconds = 0.03 seconds

The initial velocity $v_1$ is zero.

The final speed $v_2 = 73.14\ m / s$

$F * 0.03 = 73.14m$

$F * 0.03 = 73.14m\\\\F=\frac{73.14m}{0.03}\\\\F=2438m$

We must express the result of the force in terms of the weight of the ball.

We divide the expression between the acceleration of gravity

$g = 9.8\ m / s ^ 2$

$F=\frac{2438m*g}{g},\ \ m*g=w\\\\g=9.8\ m/s^2\\\\F=\frac{2438w}{9.8}\\\\F=249w$

The answer is the third option

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3 years ago

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Lorico [155]

Answer:

2nd no. positive.... 3rd no. negitive......

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3 years ago

When the valve between the 2.00-L bulb, in which the gas pressure is 2.00 atm, and the 3.00-L bulb, in which the gas pressure is

padilas [110]

Answer:

$P_{C} = 3.2\, atm$

Explanation:

Let assume that gases inside bulbs behave as an ideal gas and have the same temperature. Then, conditions of gases before and after valve opened are now modelled:

Bulb A (2 L, 2 atm) - Before opening:

$P_{A} \cdot V_{A} = n_{A} \cdot R_{u} \cdot T$