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Please include the statements
...a metal atom will *lose* electrons to form a *positive* cation and a nonmetal atom will *accept* electrons to form an *negative* anion.
Answer:
All of the above.
Explanation:
In positive deviation from Raoult's Law occur when the vapour pressure of components is greater than what is expected value in Raoult's law.
When a solution is non ideal then it shows positive or negative deviation.
Let two solutions A and B to form non- ideal solutions.let the vapour pressure of component A is
and vapour pressure of component B is
.
= Vapour pressure of component A in pure form
= Vapour pressure of component B in pure form
=Mole fraction of component A
=Mole fraction of component B
The interaction between A- B is less than the interaction A- A and B-B interaction.Therefore, the escaping tendency of liquid molecules in mixture is greater than the escaping tendency in pure form.Hence, the vapour pressure of a mixture is greater than the initial value of vapour pressure.
,![P_B>P^0_B\cdot x_B](https://tex.z-dn.net/?f=P_B%3EP%5E0_B%5Ccdot%20x_B)
Therefore, ![P_A+P_B >P^0_A\cdot x_A+P^0_B \cdot x_B](https://tex.z-dn.net/?f=P_A%2BP_B%20%3EP%5E0_A%5Ccdot%20x_A%2BP%5E0_B%20%5Ccdot%20x_B)
Therefore, the enthalpy of mixing is greater than zero and change in volume is greater than zero.
Hence, option a,b,c and d are true.