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3 years ago

In two or more complete sentences explain how to balance the chemical equation and classify its reaction type

Chemistry

2 answers:

Dafna11 [192]3 years ago

4 0

Answer:

Hi! In this case, the reactioncan be correctly balance according to this: 2Al(s) + 3CuSO4(aq) –> Al2(SO4)3(aq) + 3Cu(s).

Explanation:

In this particulary reaction,two semi-reactions happens.

One involving the metallic aluminum that suffers an oxidation reaction:

Al (s) -> Al3 + (aq) + 3e–

and another is a reduction reaction involving copper;

2e– + Cu2 + (aq) -> Cu (s)

Alexxandr [17]3 years ago

4 0

Answer:

2Al(s) + 3CuSO4(aq). --------> Al2(SO4)3(aq) + 3Cu(s)

Explanation:

This is a displacement reaction. Aluminum, being higher in the electrochemical series (higher electrode potential) displaces copper from its aqueous salt to give an aluminum salt and copper metal.

The equation is balanced with the formula of the products in mind. Since the products must be Al2(SO4)3 and 3Cu, then the stoichiometric coefficient of aluminum must be 2 on the reactant side and that of CuSO4 must be 3 on the reactants side.

This fulfils the general principle for balancing reaction equations which states that, the number of atoms of each element on the right hand side of the reaction equation, must be the same as the number of atoms of the same element on the left hand side of the reaction equation.

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True or false: a physical property is a characteristic of matter that you cannot observe or measure without changing the identit

Ganezh [65]

That is false, hope this helps.

4 0

3 years ago

A sealed 1.0L flask is filled with 0.500 mols of I_2 and 0.500 mols of Br_2. When the container achieves equilibrium the equilib

DochEvi [55]

Answer:

[IBr] = 0.049 M.

Explanation:

Hello there!

In this case, according to the balanced chemical reaction:

$I_2+Br_2\rightarrow 2IBr$

It is possible to set up the following equilibrium expression:

$K=\frac{[IBr]^2}{[I_2][Br_2]} =0.0110$

Whereas the the initial concentrations of both iodine and bromine are 0.50 M; and in terms of $x$ (reaction extent) would be:

$0.0110=\frac{(2x)^2}{(0.50-x)^2}$

Which can be solved for $x$ to obtain two possible results:

$x_1=-0.0277M\\\\x_2=0.0245M$

Whereas the correct result is 0.0245 M since negative results does not make any sense. Thus, the concentration of the product turns out:

$[IBr]=2x=2*0.0249M=0.049M$

Regards!

7 0

2 years ago

A weather balloon is filled with helium that occupies a volume of 5.57 104 L at 0.995 atm and 32.0°C. After it is released, it r

Alchen [17]

6.52 × 10⁴ L. (3 sig. fig.)

<h3>Explanation</h3>

Helium is a noble gas. The interaction between two helium molecules is rather weak, which makes the gas rather "ideal."

Consider the ideal gas law:

$P\cdot V = n\cdot R\cdot T$ ,

where

$P$ is the pressure of the gas,
$V$ is the volume of the gas,
$n$ is the number of gas particles in the gas,
$R$ is the ideal gas constant, and
$T$ is the absolute temperature of the gas in degrees Kelvins.

The question is asking for the final volume $V$ of the gas. Rearrange the ideal gas equation for volume:

$V = \dfrac{n \cdot R \cdot T}{P}$ .

Both the temperature of the gas, $T$ , and the pressure on the gas changed in this process. To find the new volume of the gas, change one variable at a time.

Start with the absolute temperature of the gas:

$T_0 = (32.0 + 273.15) \;\text{K} = 305.15\;\text{K}$ ,
$T_1 = (-14.5 + 273.15) \;\text{K} = 258.65\;\text{K}$ .

The volume of the gas is proportional to its temperature if both $n$ and $P$ stay constant.

$n$ won't change unless the balloon leaks, and
consider $P$ to be constant, for calculations that include $T$ .

$V_1 = V_0 \cdot \dfrac{T_1}{T_2} = 5.57\times 10^{4}\;\text{L}\times \dfrac{258.65\;\textbf{K}}{305.15\;\textbf{K}} = 4.72122\times 10^{4}\;\text{L}$ .

Now, keep the temperature at $T_1 =258.65\;\text{K}$ and change the pressure on the gas:

$P_1 = 0.995\;\text{atm}$ ,
$P_2 = 0.720\;\text{atm}$ .

The volume of the gas is proportional to the reciprocal of its absolute temperature $\dfrac{1}{T}$ if both $n$ and $T$ stays constant. In other words,

$V_2 = V_1 \cdot\dfrac{\dfrac{1}{P_2}}{\dfrac{1}{P_1}} = V_1\cdot\dfrac{P_1}{P_2} = 4.72122\times 10^{4}\;\text{L}\times\dfrac{0.995\;\text{atm}}{0.720\;\text{atm}}=6.52\times 10^{4}\;\text{L}$

(3 sig. fig. as in the question.).

See if you get the same result if you hold $T$ constant, change $P$ , and then move on to change $T$ .

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3 years ago

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ra1l [238]

Answer:

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3 years ago

According to the kinetic molecular theory, which statement describes an ideal gas?

djverab [1.8K]

The correct answer is option 3. There are no attractive forces between the gas particles in an ideal gas. For an ideal gas to be achieved, the molecules are far from each other as possible where no attraction or collisions happen with each molecule.

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3 years ago