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Leya [2.2K]
3 years ago
13

The value of ΔS° for the oxidation of solid elemental sulfur to gaseous sulfur dioxide, S (s, rhombic) + O2 (g) → SO2 (g) is ___

_____ J/K⋅mol. The value of S° for the oxidation of solid elemental sulfur to gaseous sulfur dioxide, S (s, rhombic) + O2 (g) SO2 (g) is ________ J/Kmol. +248.5 +485.4 +11.6 -11.6 -248.5
Chemistry
1 answer:
Alexus [3.1K]3 years ago
3 0

Answer:

\large \boxed{\text{11.3 J$\cdot$K$^{-1}$mol$^{-1}$}}

Explanation:

You can calculate the entropy change of a reaction by using the standard molar entropies of reactants and products.

The formula is

\displaystyle \Delta_{r} S^{\circ} = \sum_n {nS_{\text{products}}^{\circ} - \sum_{m} {mS_{\text{reactants}}^{\circ}}}

The equation for the reaction is

                        S(s, rhombic) + O₂(g) ⟶ SO₂(g)

ΔS°/J·K⁻¹mol⁻¹         31.8            205.0      248.1

\Delta_{r} S^{\circ} = 248.1 - (31.8 + 205.0) =248.1 - 236.8 = \large \boxed{\textbf{11.3  J$\cdot$K$^{-1}$mol$^{-1}$}}

The difference probably arises for our use of different sources for the molar entropies.

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How many liters of carbon dioxide will 0.5 moles of lithium hydroxide (LiOH) absorb?
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