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Leya [2.2K]
3 years ago
13

The value of ΔS° for the oxidation of solid elemental sulfur to gaseous sulfur dioxide, S (s, rhombic) + O2 (g) → SO2 (g) is ___

_____ J/K⋅mol. The value of S° for the oxidation of solid elemental sulfur to gaseous sulfur dioxide, S (s, rhombic) + O2 (g) SO2 (g) is ________ J/Kmol. +248.5 +485.4 +11.6 -11.6 -248.5
Chemistry
1 answer:
Alexus [3.1K]3 years ago
3 0

Answer:

\large \boxed{\text{11.3 J$\cdot$K$^{-1}$mol$^{-1}$}}

Explanation:

You can calculate the entropy change of a reaction by using the standard molar entropies of reactants and products.

The formula is

\displaystyle \Delta_{r} S^{\circ} = \sum_n {nS_{\text{products}}^{\circ} - \sum_{m} {mS_{\text{reactants}}^{\circ}}}

The equation for the reaction is

                        S(s, rhombic) + O₂(g) ⟶ SO₂(g)

ΔS°/J·K⁻¹mol⁻¹         31.8            205.0      248.1

\Delta_{r} S^{\circ} = 248.1 - (31.8 + 205.0) =248.1 - 236.8 = \large \boxed{\textbf{11.3  J$\cdot$K$^{-1}$mol$^{-1}$}}

The difference probably arises for our use of different sources for the molar entropies.

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anygoal [31]

Answer:

5 g

Explanation:

The heat required to vaporize ice is the sum of

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ii) Heat required to raise the temperature from  0°C to 100°C

iii) Heat required to vaporize water at 100°C

Thus;

H = nLfus + ncθ + nLvap

H= n(Lfus + cθ + Lvap)

Lfus = 6.01 kJ/mol

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n =?

2100 = n(6.01  + 75.38(100) + 41)

n = 2100 KJ/7585.01 kJ/mol

n = 0.277 moles

Mass of water = number of moles * molar mass

Mass of water = 0.277 moles * 18 g/mol

Mass of water =  5 g

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3 years ago
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Suppose a liquid level from 5.5 to 8.6 m is linearly converted to pneumatic pressure from 3 to 15 psi. What pressure will result
wlad13 [49]

Answer:

a) P = 9.58 psi for  h=7.2 m

b) P=4.7 psi for h=5.94 m

Explanation:

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where p₀= initial pressure , ρ=density , g = gravity

then he variation of the liquid level Δh will produce a variation of pressure of

ΔP= ρ*g*Δh → ΔP/Δh =  ρ*g = ( 15 psi - 3 psi) /( 8.6 m - 5.5 m)  = 12/3.1 psi/m

if the liquid level is converted linearly

P = P₁ + ΔP/Δh*(h -h₁)

therefore choosing  P₁ = 3 psi and h₁= 5.5 m , for h=7.2 m

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then P = 9.58 psi for  h=7.2 m

for P=4.7 psi

4.7 psi = 3 psi  + 12/3.1 psi/m *(h -5.5 m)

h = (4.7 psi - 3 psi)/ (12/3.1 psi/m) + 5.5 m = 5.94 m

then P=4.7 psi for h=5.94 m

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