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labwork [276]
3 years ago
5

A Ford Mustang was at a stop sign. The driver then stepped on the gas pedal and within 6 seconds was travelling at 36 m/s. What

was the rate of acceleration?
A. 36 m/s²
B. 216 m/s²
C. 10 m/s²
D. 6 m/s²
Physics
1 answer:
velikii [3]3 years ago
6 0

Answer:

D. 6 m/s²

Explanation:

Given parameters:

Initial velocity  = 36m/s

Final velocity  = 0m/s

Time taken = 6s

Unknown:

Acceleration of the car  = ?

Solution:

Acceleration is the rate of change of velocity with time;

 Mathematically;

     Acceleration   = \frac{v - u}{t}

v is the final velocity

u is the initial velocity

t is the time

 Acceleration  = \frac{0 - 36}{6}   = -6m/s

The acceleration of the car must have been 6m/s²

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The prop blades of an airplane spin with a linear velocity of 875 m/s and have a centripetal acceleration on the farthest edge o
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<h3>Radius of the prop blade</h3>

The radius of the prop blade of an airplane is calculated as follows;

a = v²/r

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Thus, the radius of the prop blade of an airplane is determined as 4.25 m.

Learn more about centripetal acceleration here: brainly.com/question/79801

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