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3 years ago

How many moles of water will be produced if 14 moles of hydrogen are mixed with 7 moles of oxygen gas

Chemistry

1 answer:

IrinaK [193]3 years ago

5 0

Using simply rational here:

1 Water= two hydrogen atoms+ 1 oxygen atom

The numbers provided would create seven water molecules based on having fourteen hydrogen’s (which would be seven times the two required for water) and seven oxygen.

So, 7

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A. Clearly draw the Lewis structure for the PBr4- ion. Show your math where

Nataliya [291]

Answer:

Br-P-Br

Explanation:

To calculate the valance electrons, look at the periodic table to find the valance electrons for each atom and add them together. P is in column 5A, so it has 5, Br is in column 7A, so it has 7 (multiply by 4 since there are 4 Br atoms to give 28) and there is a 1- charge, so add one more electron. 5+28+1=34, so there are 34 electrons to place. P would be the central atom, so place it in the middle. Place each Br around the P (as shown above) with a a single line connecting it. Each line represents 2 electrons, so 8 total have been place, leaving 26 remaining. Place 6 electrons around each Br (2 on each of the unbonded sides), which leaves 2 electrons remaining. The remaining pair of unbound electrons will be attached to the P between any two Br atoms. Phosphorus doesn't have to follow the octet rule, so it actually ends up with 10 valance electrons.

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2 years ago

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Carbon dioxide is produced by the human body through

blsea [12.9K]

Answer:

Respiration

I hope this helps!

8 0

3 years ago

What volume (in mL) of a 0.200 MHNO3 solution is required to completely react with 27.6 mL of a 0.100 MNa2CO3 solution according

ladessa [460]

Answer:

There is 27.6 mL of a 0.200 M HNO3 solution required

Explanation:

Step 1: The balanced equation is:

Na2CO3(aq)+2HNO3(aq)→2NaNO3(aq)+CO2(g)+H2O(l)

This means for 1 mole Na2CO3 consumed, there is consumed 2 mole of HNO3 and there is produced 2 moles of NaNO3, 1 mole of CO2 and 1 mole of H2O

Step 2: Calculating moles of Na2CO3

moles of Na2CO3 =volume of Na2CO3 * Molarity of Na2CO3

moles of Na2CO3 = 27.6 *10^-3 * 0.1 M = 0.00276 moles

Step 3: Calculating moles of HNO3

In the balanced equation, we can see that for 1 mole of Na2CO3 consumed, there are consumed 2 moles of HNO3.

So for 0.00276 moles consumed of Na2CO3, there are consumed 0.00552 moles of HNO3.

This means 0.00276 moles of the base Na2CO3 would react with 0.00552 moles of the acid HNO3

Step 4: Calculating the volume of HNO3

volume of HNO3 = moles of HNO3 / Molarity of HNO3

volume of HNO3 = 0.00552 moles / 0.200 M = 0.0276 L

0.0276 L = 27.6 ml

There is 27.6 mL of a 0.200 M HNO3 solution required

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2 years ago

The smallest unit that can exist as an element and still have the properties of that element is a(n):

Yuri [45]

The smallest unit that can exist as an element and still have proprieties of that element is an Atom

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2 years ago

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How many moles are in 987 grams of Ra(OH)2

ra1l [238]

Molar mass Ra(OH)2 = 260 g/mol
Moles = 987 g / 260 = 3.80 moles

7 0

3 years ago

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