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gizmo_the_mogwai [7]
3 years ago
10

How does a filament work together with a fuse in holiday lights?

Physics
1 answer:
Eduardwww [97]3 years ago
5 0

Answer:

I hope that this helps you :)

Explanation:

We're getting into the holiday spirit here at the Department of Energy. Our stockings are hung by the chimney with care and we have strings of lights decorating our cubicles. While stringing up lights, I wanted to learn how exactly holiday lights work. Here’s what I discovered.

Holiday lights are a great way to learn about the flow of electric current. In a simple circuit, including one in an incandescent light bulb, electricity travels through a closed circuit, passing over a filament, causing it to glow brightly. The more current that passes over a filament, the hotter it will get, the brighter it will burn, and the quicker it will burn out. If the circuit is broken, or open, no electricity will pass over the filament and it will not light. If the current is too great, the filament will melt, or blow out, causing the circuit to become open.

But we want more than one light to shine on our Christmas tree or along the roofs of our homes. If you want to connect multiple light bulbs to the same power source, there are two ways to do that: either attach the lights in series or parallel.

When lights are attached in series, the electricity passes from the power source to the first light, and then from light to light until it returns to the power source. In this setup, when a filament within any one bulb blows out, it creates an open circuit in the wiring. As we mentioned earlier, when a circuit is incomplete, or open, electricity fails to pass through any of the wires, causing all the lights to go out.

When lights are attached in parallel, each light is on its circuit to the power source. If one filament burns out, it does not affect the remaining lights, as they each continue to be in a closed circuit with the power source

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Mariner 10 was the first to visit this planet in 1974. Which planet is this?
MissTica
<h2>Answer: Mercury </h2>

The Mariner 10 probe was launched by NASA on November 3rd, 1973, with the purpose of exploring the characteristics of two planets in the solar system that were closest to the Sun, Mercury and Venus.

In addition, it was launched to explore the atmosphere and surface of both planets and prove that it was possible to use gravitational assistance (also called slingshot effect, a special orbital maneuver in order to use the gravitational field energy of a planet or massive body to accelerate or slow the probe and change the direction of its trajectory) in long interplanetary trips to save fuel.

In this case, Mariner 10 first arrived at Venus and succeded in using its gravitational field to accelerate its trajectory towards Mercury.

5 0
3 years ago
If three forces F1 = 20N, 300NE, F2 = 50N along W, F3 = 40N 500NW act on a body. Find the resultant in magnitude and direction.​
patriot [66]

Answer:

110N north west

Explanation:

.........

4 0
3 years ago
Let us be two cylindrical conductors connected in parallel, to which a potential difference of V = 170V is applied. The two cond
PSYCHO15rus [73]

The equivalent resistance of the two cylindrical conductors connected in parallel is 466 ohm.

<h3>Resistance</h3>

Resistance is a measure of the opposition to flow of electric current. It is measured in ohms.

It is given by the formula:

R=\rho\frac{l}{A} \\\\where\ l=length,A=area,\rho=resistivity

Given that R₂ = 469 ohm, hence:

R_2=\rho\frac{l_2}{A_2} \\\\469=\rho\frac{l_2}{\pi r_2^2}

But l₁ = 6l₂, r₁ = (1/5)r₂, hence:

R_1=\rho \frac{l_1}{A_1}=\rho *\frac{6l_2}{[\pi (1/5)r_2]^2} =150 * \rho \frac{l_2}{[\pi r_2]^2}=30*469=70350\ ohm

The equivalent resistance (R) is:

R=\frac{R_1R_2}{R_1+R_1}=\frac{469*70350}{469+70350}  =466\ ohm

The equivalent resistance of the two cylindrical conductors connected in parallel is 466 ohm.

Find out more on resistance at: brainly.com/question/17563681

3 0
3 years ago
A car speeds up while the engine delivers constant power. Is the acceleration greater at the beginning of this process or at the
dsp73

Answer:

The acceleration greater at the beginning of this process

Explanation:

The car when starting to move is necessary an acceleration therefore at the beginning of the movement there is an acceleration. The engine power is at a constant value so that when the car reaches the maximum speed (constant speed) at that power there will be no acceleration.

That is to say, at constant speed = zero acceleration

And of course this final null acceleration will be less than the initial acceleration so that the car starts to move .

4 0
3 years ago
A student measures the mass of a 1.0 kg standard bar. He obtains measurements of 0.77 kg, 0.78 kg, and 0.79 kg. Which describes
Vadim26 [7]

Complete question

A student measures the mass of a 1.0 kg standard bar. He obtains measurements of 0.77 kg, 0.78 kg, and 0.79 kg. Which describes his measurements

a)precise but not accurate

b)accurate but not precise

c)neither precise nor accurate

d)both precise and accurate

Answer:

The measurement is precise but not accurate

Explanation:

A measurement can either be precise or accurate.

  • A Precise measurement describes how close the measured values are to each other.
  • An accurate measurement describes how close a measured value is to the true value.

In this question, the measured values (0.77 kg, 0.78 kg and 0.79 kg) are far from the true value (1.0 kg), therefore the measurement is not accurate.

However, the measured values (0.77 kg, 0.78 kg and 0.79 kg) are close to each other, therefore the measurement is precise.

Therefore the correct option is 'a' the measurement is precise but not accurate

4 0
3 years ago
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