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elena-s [515]
3 years ago
10

Pls help and no links thankyou <3

Mathematics
1 answer:
Hitman42 [59]3 years ago
8 0
Do the second one hope this helps
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I need help please <br>​
Triss [41]
She paid $3.28 per gallon.

24.60 divided by 7.5 equals 3.28.
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3 years ago
2<br> Solve for k.<br> -8k+ 6 = –10k + 10<br> k
Sever21 [200]

Answer:

k=2

Step-by-step explanation:

8 0
3 years ago
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Factor 4x 2 + 12x + 5 . (2x + 5)(2x + 1)
swat32
4x^2 + 12x + 5=4x^2+2x+10x+5 \\  \\ =2x(2x+1)+5(2x+1)=(2x+5)(2x+1) \\  \\ \therefore4x^2+12x+5=(2x+5)(2x+1)
8 0
3 years ago
NEED HELP ASAP<br> Given G (-6,5) and H (2, -7), what is the length of GH
lesya692 [45]

\bold{\huge{\green{\underline{ Solution }}}}

\bold{\underline{ Given}}

  • <u>We </u><u>have </u><u>given </u><u>that </u><u>the </u><u>coordinates </u><u>of </u><u>the </u><u>end </u><u>point </u><u>G </u><u>and </u><u>H </u><u>are </u><u>(</u><u> </u><u>-</u><u>6</u><u>,</u><u>5</u><u>)</u><u> </u><u>and </u><u>(</u><u> </u><u>2</u><u>,</u><u> </u><u>-</u><u>7</u><u> </u><u>)</u>

\bold{\underline{To  \: Find :- }}

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>length </u><u>of </u><u>GH </u>

\bold{\underline{Let's \:  Begin :- }}

The coordinates of G = ( -6 , 5 )

The coordinates of H = ( 2 , - 7 )

<u>According </u><u>to </u><u>the </u><u>distance </u><u>formula</u><u>, </u><u> </u><u>we </u><u>get </u><u>:</u><u>-</u><u> </u>

\purple{\bigstar}\boxed{\sf{Distance\:\:GH=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2\;}}}

  • <u>Here</u><u>, </u><u> </u><u>x1</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>,</u><u> </u><u>x2</u><u> </u><u>=</u><u> </u><u>2</u><u> </u><u>and </u><u>y1</u><u> </u><u>=</u><u> </u><u>5</u><u> </u><u>,</u><u> </u><u>y2</u><u> </u><u>=</u><u> </u><u>-</u><u>7</u>

<u>Subsitute </u><u>the </u><u>required </u><u>values </u><u>in </u><u>the </u><u>above </u><u>formula </u>

\sf{ Distance \:GH = √( -6 - 2)² + ( 5 -(-7))²}

\sf{Distance\:GH= √(-8)^2+(5 + 7)^2}

\sf{Distance\:GH=√(-8)^2+(12)^2}

\sf{ Distance \:GH =√64 + 144 }

\sf{ Distance \:GH =√ 208}

\sf{ Distance\: GH = √ 2 × 2 × 2 × 2 × 13}

\sf{ Distance \:GH = 4√13}

\sf{\red{ Hence\: the \: length\:of \: GH \: is \: 4√13 \: units}}

3 0
2 years ago
23 over.30 ÷20 over 24
alexgriva [62]

Remark

Don't try and do this all at once. Break it down, otherwise you'll have layers and brackets all over the place.

Step One

Find 23/0.3

X = 23/0.3 = 76.7

Step Two

Now Divide by 20

x1 = 76.7 / 20

x1 = 3.83

Step Three

Take this result and put it over 24

x2 = x1/24

x2 = 3.83 / 24

x2 = 0.1597 <<<< Answer

6 0
3 years ago
Read 2 more answers
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