(x+3)(x^2-3x+9)
this gets the x^3 while the 3x cancels out and 3*9=27
hope this helps although i didn't explain very well :)
F(x)=x^3+x^2-9x-9
x^2(x+1)-9(x+1)
=(x+1)(x^2-9)
=(x+1)(x+3)(x-3)
Hope that this helps
Note that the 2nd equation can be re-written as y=8x-10.
According to the second equation, y=x^2+12x+30.
Equate these two equations to eliminate y:
8x-10 = x^2+12x+30
Group all terms together on the right side. To do this, add -8x+10 to both sides. Then 0 = x^2 +4x +40. You must now solve this quadratic equation for x, if possible. I found that this equation has NO REAL SOLUTIONS, so we must conclude that the given system of equations has NO REAL SOLUTIONS.
If you have a graphing calculator, please graph 8x-10 and x^2+12x+30 on the same screen. You will see two separate graphs that do NOT intersect. This is another way in which to see / conclude that there is NO REAL SOLUTION to this system of equations.
The linear equation in standard form is:
6x - 7y = -11
Which is the last option.
<h3>
How to get the equation of the line?</h3>
The line in slope-intercept form is written as:
y = a*x + b
We can see that the line passes through the points (-3, -1) and (1/2, 2), then the slope is:
Then we can write:
y = (6/7)*x + b
To find the value of b, we use the first point. It means that when x = -3, the value of y is -1, then we get:
-1 = (6/7)*-3 + b
-1 + 18/7 = b
-7/7 + 18/7 = b
11/7 = b
Then the equation is:
y = (6/7)*x + 11/7
If we multiply both sides by 7 we get:
7y = 6x + 11
Now we move the term with "x" to the left:
7y - 6x = 11
That is the line in standard form.
If we multiply both sides by -1, we get the last option:
6x - 7y = -11
If you want to learn more about linear equations:
brainly.com/question/1884491
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Answer: Wowwww that ain't good at all and sooo not fair if Peter worked three more days than Jill but still only got twenty bucks. That's pretty sad.
Step-by-step explanation:
