The function that you will use in order to test the reverse route back toward the original host is known as Extended ping. Thus, the correct option for this question is B.
<h3>What is Ping and traceroute for?</h3>
Ping and traceroute are the common commands you can effectively utilize in order to troubleshoot network problems. Ping is a simple command that can typically test the reachability of a device on the network. While traceroute is a command you use to 'trace' the route that a packet takes when traveling to its destination.
Extended ping permits a router's ping command to use The router's LAN IP address from within the subnet, fully testing the route back to the subnet. A standard ping often does not test the reverse route that you need to back toward the original host.
Therefore, the function that you will use in order to test the reverse route back toward the original host is known as Extended ping. Thus, the correct option for this question is B.
To learn more about Ping and traceroute, refer to the link:
brainly.com/question/28333920
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Answer:
False
Explanation:
The two most important fields of expertise for their career were not defined as architecture and mathematics by architects.
It offers expertise and expertise to architects and engineers that can not be gained by practicing alone.
Answer:
The mass of car in slug =108.5 slug.
The mass of car in kilogram =1575 Kg.
Explanation:
Given that
Mass of car = 3500 lbs
We know that
1 lbs =0.031 slug
So
3500 lbs = 0.031 x 3500 slug
So the mass of car in slug =108.5 slug.
We know that
1 lbs =0.45 kilograms
so
3500 lbs = 3500 x 0.45 Kg
So the mass of car in kilogram =1575 Kg.
Answer:
The original length of the specimen is found to be 76.093 mm.
Explanation:
From the conservation of mass principal, we know that the volume of the specimen must remain constant. Therefore, comparing the volumes of both initial and final state as state 1 and state 2:
Initial Volume = Final Volume
πd1²L1/4 = πd2²L2/4
d1²L1 = d2²L2
L1 = d2²L2/d1²
where,
d1 = initial diameter = 19.636 mm
d2 = final diameter = 19.661 mm
L1 = Initial Length = Original Length = ?
L2 = Final Length = 75.9 mm
Therefore, using values:
L1 = (19.661 mm)²(75.9 mm)/(19.636 mm)²
<u>L1 = 76.093 mm</u>
vₐ = 0.771 ft/s
vb = -1.54 ft/s
<u />
<u>Explanation:</u>
<u />
Block A:
F = ma
Nₐ = - 60 cos60° = 0
Nₐ = 30 lb
Fₐ = 0.1 X 30 = 3lb
Block B:
F = ma
Nb = - 40 cos30° = 0
Nb = 34.64lb
Fb = 0.1 X 34.64 = 3.464lb
T1 + ∑U = T2
(0 + 0) + 60 sin 60° |Δsₐ| - 40 sin 30° |Δsb| - 3|Δsₐ| - 3.464 |Δsb|
= 1/2 (60/32.2) vₐ² + 1/2 (40/32.2) vb²
and
2vₐ = - vb
On solving, we get
vₐ = 0.771 ft/s
vb = -1.54 ft/s
