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Rama09 [41]
3 years ago
12

A car is traveling at 36 km/h on an acceleration lane to a freeway. What acceleration is required to obtain a speed of 72 km/h i

n a distance of 100m? What time is required to travel this distance?
Engineering
1 answer:
dmitriy555 [2]3 years ago
6 0

First, write down the information given and the change units if necessary (we must have similar units to operate on).

Initial speed, u = 36 km/h = 10 m/s

Final speed, v = 72 km/h = 20 m/s

Distance, s = 100 m

We know that

{v}^{2}  -  {u}^{2}  = 2as \\  {20}^{2}  -  {10}^{2}  = 2 \times a \times 100 \\ 400 - 100 = 200 \times a \\ a =  \frac{300}{200 }  =  \frac{3}{2}  \: m {s}^{ - 2}

Now, we substitute v, u, and a in the formula

v = u + at \\ 20 = 10 +  \frac{3}{2} t \\  \frac{3}{2} t = 10 \\ 3t = 20 \\ t =  \frac{20}{3}  = 6.67 \: seconds

Please mark Brainliest if this helps!

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