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IceJOKER [234]
3 years ago
7

A volcanic ash layer between sedimentary rock layers is used by geologists to

Chemistry
1 answer:
lozanna [386]3 years ago
8 0
I believe the answer is - Correlate widely separated sedimentary rock layers
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Radium has a half-life of 1,620 years. In how many years will a 1 kg sample of radium decay and reduce to 0.125 kg of radium?
Tasya [4]
We can calculate years by using the half-life equation. It is expressed as:

A = Ao e^-kt

<span>where A is the amount left at t years, Ao is the initial concentration, and k is a constant.

</span>From the half-life data, we can calculate for k.

1/2(Ao) = Ao e^-k(1620)
<span>k = 4.28 x 10^-4
</span>
0.125 = 1 e^-<span>4.28 x 10^-4 (</span>t)
t = 4259 years
7 0
2 years ago
Read 2 more answers
A force of 5000 newtons is applied to a 1200 kg car at rest. What is its acceleration?
insens350 [35]
The formula for acceleration if rearranged based on the force equation is- force over mass. So 5000/1200=4.16

Your answer is 4 m/s squared.
4 0
2 years ago
The lattice energy of a salt is related to the energy required to separate the ions. For which of the following pairs of ions is
kati45 [8]

Answer:

(A) Mg²⁺ and O²⁻

Explanation:

6 0
2 years ago
In his version of the periodic table, mendeleev based his arrangement of the elements on an element's _________. atomic number c
sammy [17]
ʜᴇʟʟᴏ ᴛʜᴇʀᴇ!

In his version of the periodic table, Mendeleev based his arrangement of the elements on an element's atomic mass.

нσρє тнιѕ нєℓρѕ уσυ!
gσσ∂ ℓυ¢к :)
нανє α gяєαт ∂αу  

- нαηηαн ❤
4 0
3 years ago
Using Equation (10), calculate [Ag+] in the cell, where it is in equilibrium with 1 M Cl- ion. (Ecell in Equation (10) is the ne
mixer [17]

Answer:

7.16x10⁻⁸M = [Ag+]

Explanation:

Using the equation:

E(Cell) =E⁰ - 0.0592/2 • log ([Cu2+]/[Ag+]²)

<em>Where E</em>⁰<em>= 0.4249V</em>

<em>E(Cell) = -(-0.0019V) -Measured value-</em>

<em>[Cu2+] = 1M</em>

<em />

Replacing:

0.0019V = 0.4249V - 0.0592/2 • log (1M/[Ag+]²)

-0.423V = - 0.0296 • log (1M/[Ag+]²)

14.29 = log (1M/[Ag+]²)

1.95x10¹⁴ = 1M / [Ag+]²

[Ag+]² = 5.12x10⁻¹⁵M

7.16x10⁻⁸M = [Ag+]

5 0
2 years ago
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