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son4ous [18]
2 years ago
6

What mass of Ca(NO3)2 is equal to 0.75 moles of this substance?

Chemistry
1 answer:
sattari [20]2 years ago
5 0

Answer:

Ca - 63.546 g

2N - 28.014 g

2O3 - 96 g

Ca(NO3)2 = 187.56 g

187.56 g x 0.75 mol = 140.67 g

Explanation:

Hope this helps

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If 2.0 g of copper(II) chloride react with excess sodium nitrate, what mass of sodium chloride is formed in this double replacem
cluponka [151]

Taking into account the reaction stoichiometry, 1.729 grams of NaCl is formed.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

CuCl₂ + 2 NaNO₃ → Cu(NO₃)₂ + 2 NaCl

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • CuCl₂: 1 mole
  • NaNO₃: 2 moles
  • Cu(NO₃)₂ : 1 mole
  • NaCl: 2 moles

The molar mass of the compounds is:

  • CuCl₂: 134.44 g/mole
  • NaNO₃: 85 g/mole
  • Cu(NO₃)₂ : 187.54 g/mole
  • NaCl: 58.45 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • CuCl₂: 1 mole ×134.44 g/mole= 134.44 grams
  • NaNO₃: 2 moles ×85 g/mole= 170 grams
  • Cu(NO₃)₂ : 1 mole ×187.54 g/mole= 187.54 grams
  • NaCl: 2 moles ×58.45 g/mole= 116.9 grams

<h3>Mass of NaCl formed</h3>

The following rule of three can be applied: If by stoichiometry of the reaction 134.44 grams of CuCl₂ form 116.9 grams of NaCl, 2 grams of CuCl₂ form how much mass of NaCl?

mass of NaCl=\frac{2 grams of CuCl_{2}x116.9 grams of NaCl }{134.44grams of CuCl_{2}}

<u><em>mass of NaCl= 1.739 grams</em></u>

Finally, 1.729 grams of NaCl is formed.

Learn more about the reaction stoichiometry:

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2 years ago
¿Por qué el volcán causa una explosión?
never [62]
Why does the volcano cause an explosion?
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Over the years, the thermite reaction has been used for welding railroad rails, in incendiary bombs, and to ignite solid-fuel ro
melamori03 [73]

<u>Answer:</u> The mass of nickel (II) oxide and aluminium that must be used is 18.8 g and 4.54 g respectively.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For nickel:</u>

Given mass of nickel = 14.8 g

Molar mass of nickel = 58.7 g/mol

Putting values in equation 1, we get:

\text{Moles of nickel}=\frac{14.8g}{58.7g/mol}=0.252mol

For the given chemical reaction:

3NiO(s)+2Al(s)\rightarrow 3Ni(l)+Al_2O_3(s)

  • <u>For nickel (II) oxide:</u>

By Stoichiometry of the reaction:

3 moles of nickel are produced from 3 moles of nickel (II) oxide

So, 0.252 moles of nickel will be produced from \frac{3}{3}\times 0.252=0.252mol of nickel (II) oxide

Now, calculating the mass of nickel (II) oxide by using equation 1:

Molar mass of nickel (II) oxide = 74.7 g/mol

Moles of nickel (II) oxide = 0.252 moles

Putting values in equation 1, we get:

0.252mol=\frac{\text{Mass of nickel (II) oxide}}{74.7g/mol}\\\\\text{Mass of nickel (II) oxide}=(0.252mol\times 74.7g/mol)=18.8g

  • <u>For aluminium:</u>

By Stoichiometry of the reaction:

3 moles of nickel are produced from 2 moles of aluminium

So, 0.252 moles of nickel will be produced from \frac{2}{3}\times 0.252=0.168mol of aluminium

Now, calculating the mass of aluminium by using equation 1:

Molar mass of aluminium = 27 g/mol

Moles of aluminium = 0.168 moles

Putting values in equation 1, we get:

0.168mol=\frac{\text{Mass of aluminium}}{27g/mol}\\\\\text{Mass of aluminium}=(0.168mol\times 27g/mol)=4.54g

Hence, the mass of nickel (II) oxide and aluminium that must be used is 18.8 g and 4.54 g respectively.

4 0
3 years ago
Determine whether each of the descriptions of matter describes a heterogeneous mixture, a homogeneous mixture, or a pure substan
lorasvet [3.4K]

Answer: a. two substances present; two phases present  : Heterogeneous mixture

b. two substances present; one phase present : Homogeneous mixture

c. one substance present; one phase present : pure substance.

d. one substance present; two phases present: Heterogeneous mixture

Explanation:

A pure substance is a substance which contains definite composition of only one type of component. Hence, it cannot be separated by physical means.

Mixture is a substance which contains two or more than two types of components and they can be separated by physical means as well.

Homogeneous mixtures: It is a mixture that has uniform composition throughout the solution and the particle size or shapes are not different. There is no physical boundary between the dispersed phase and dispersion medium.

Heterogeneous mixtures: It is a mixture that has non-uniform composition throughout the solution and the particle size or shapes are also different.  There is a physical boundary between the dispersed phase and dispersion medium.

5 0
3 years ago
When glucose is fermented, ethanol is formed together with ………………….
levacccp [35]

Answer:

carbon dioxide and oxygen

3 0
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