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3 years ago

How are dams made do they just freeze time?

Physics

2 answers:

lina2011 [118]3 years ago

6 0

Answer:

Gravity dams are so named because they are held to the ground by gravity – they weigh a lot, and are typically made from concrete or stone. Engineers must de-water the river where the dam is meant to be built. This is done by diverting the river through a tunnel that runs around the intended construction zone.

bearhunter [10]3 years ago

6 0

Answer:First, they dug tunnels from below the dam to above the dam. Then, they put the cofferdam in place, and opened the tunnels. The water flowed around the site where the permanent dam would be built until they were done, at which point the cofferdam was removed.

Explanation:hope this helped

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Water enters a shower head through a pipe of radius 0.0112 m at 3.25 m/s. What is it’s volume flow rate? (Unit= m^3/s)

kenny6666 [7]

Answer:

$1.28 \times 10 ^{-3} m^3/s$

Explanation:

Given that the radius of the pipe, r =0.0112 m

So, the area of the cross-section, $a= \pi (0.0112)^2 = 3.941\times 10^{-4} m^2$

Speed of water in the pipe, v=3.25 m/s

Volume flow rate = $av= 3.941\times 10^{-4} \times 3.25 = 1.28\times 10 ^{-3} m^3/s$

Hence, the volume flow rate is $1.28 \times 10 ^{-3} m^3/s$

7 0

3 years ago

Read 2 more answers

The left face of a biconvex lens has a radius of curvature of magnitude 11.7 cm, and the right face has a radius of curvature of

SIZIF [17.4K]

Answer:

Explanation:

R1 = + 11.7 cm

R2 = - 18.7 cm

n = 1.52

(a) Use lens maker formula

$\frac{1}{f}=\left ( n-1 \right )\left ( \frac{1}{R_{1}}-\frac{1}{R_{2}} \right )$

$\frac{1}{f}=\left ( 1.52-1 \right )\left ( \frac{1}{11.7}}+\frac{1}{18.7} \right )$

$\frac{1}{f}=\frac{0.52\times 30.4}{218.79}$

f = 13.84 cm

(b)

R1 = + 18.7 cm

R2 = - 11.7 cm

n = 1.52

(a) Use lens maker formula

$\frac{1}{f}=\left ( n-1 \right )\left ( \frac{1}{R_{1}}-\frac{1}{R_{2}} \right )$

$\frac{1}{f}=\left ( 1.52-1 \right )\left ( \frac{1}{18.7}}+\frac{1}{11.7} \right )$

$\frac{1}{f}=\frac{0.52\times 30.4}{218.79}$

f = 13.84 cm

5 0

4 years ago

Please help

mafiozo [28]

Answer:

displacement=specific distance

*Velocity=∆displacement/time

*acceleration=∆velocity/time

7 0

3 years ago

If a machine has an efficiency of 94% and you apply 574J of work, how much work do you get out of the machine

Mariana [72]

<h3>Answer:</h3>

539.56 Joules

<h3>Explanation:</h3>

Efficiency of a machine is the ratio of work output to work input expressed as a percentage.

Efficiency = (work output/work input) × 100%
Efficiency of a machine is not 100% because so energy is lost due to friction of the moving parts and also as heat.

In this case;

Efficiency = 94%

Work input = 574 Joules

Therefore, Assuming work output is x

94% = (x/574 J) × 100%

0.94 = (x/574 J)

Thus, you get work of 539.56 J from the machine

7 0

3 years ago

Because of surface tension, it is possible, with care, to support an object heavier than water on the water surface. The maximum

boyakko [2]

Answer: