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kherson [118]
4 years ago
12

A football is thrown vertically with an initial velocity of 33m/s. Calculate the velocity of the ball when it’s height increased

5m
Physics
1 answer:
tatyana61 [14]4 years ago
5 0

The final velocity becomes 31.48 m/s

<u>Explanation:</u>

Given:

Initial velocity, u = 33 m/s

Height, h = 5m

Final velocity, v = ?

According to Newton's law:

v² - u² = 2gh

where,

g is the acceleration due to gravity and

g = 9.8 m/s²

On substituting the values we get:

v^2 - (33)^2 = 2 X -9.8 X 5\\\\v^2 - 1089 = -98\\\\v^2 = 991\\\\v = 31.48 m/s

Therefore, the final velocity becomes 31.48 m/s

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A block with mass m =6.4 kg is hung from a vertical spring. When the mass hangs in equilibrium, the spring stretches x = 0.28 m.
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mass of block (m)= 6.4 Kg

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   f = \dfrac{1}{2\pi}\sqrt{\dfrac{224}{6.4}}

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d)  a_{max} = v \omega

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e)  Y =- A sin (\omega t)

    A = \dfrac{v}{\omega}

    A = \dfrac{4.04}{5.92}

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    Y =- 0.682 \times sin (5.92 \times 0.42)

    Y =- 0.42

Force =m \omega^2 |Y|

          =6.4 \times 5.92^2\times 0.42

F = 94.20 N

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