2 years ago

Some_____

Engineering

1 answer:

Thepotemich [5.8K]2 years ago

5 0

Answer:

it’s IGS

Explanation:

because i read

You might be interested in

Given a square matrix [A], write a single line MATLAB command that will create a new matrix [Aug] that consists of the original

Liono4ka [1.6K]

Answer:

Consider A is square matrix of order 4 x 4 generated using magic function. Augmented matrix can be generated using:

Aug=[A eye(size(A))]

Above command is tested in MATLAB command window and is attached in figure below

8 0

2 years ago

In the ____ sector; occupations range from maintenance/service technicians, light vehicle technicians, and heavy vehicle technic

Len [333]

Answer:

Explanation:

becuase this is the best optimal answer when it comes to this particular situation of choice

5 0

1 year ago

If 9 + 10 = 21, then what is 10 + 10?

Katen [24]

The answer would be 23 because the engines in a horse is a amount of 9 engines in 69 cars

6 0

2 years ago

Read 2 more answers

1) (35 pts) For the curved lifting bar, calculate the stresses at A, B, and the centroid of the section.

Juliette [100K]

I know the Answer but first you should add me as Brainliest and I Will edit this to Answer.

3 0

2 years ago

The exhaust steam from a power station turbine is condensed in a condenser operating at 0.0738 bar(abs). The surface of the heat

lozanna [386]

Answer:

Percentage change 5.75 %.

Explanation:Given ;

Given

Pressure of condenser =0.0738 bar

Surface temperature=20°C

Now from steam table

Properties of steam at 0.0738 bar

Saturation temperature corresponding to saturation pressure =40°C

$h_f= 167.5\frac{KJ}{Kg},h_g= 2573.5\frac{KJ}{Kg}$

So Δh=2573.5-167.5=2406 KJ/kg

Enthalpy of condensation=2406 KJ/kg

So total heat=Sensible heat of liquid+Enthalpy of condensation

$Total\ heat\ =C_p\Delta T+\Delta h$

Total heat =4.2(40-20)+2406

Total heat=2,544 KJ/kg

Now film coefficient before inclusion of sensible heat

$h_1=\dfrac{\Delta h}{\Delta T}$

$h_1=\dfrac{2406}{20}$

$h_1=120.3\frac{KJ}{kg-m^2K}$

Now film coefficient after inclusion of sensible heat

$h_2=\dfrac{total\ heat}{\Delta T}$

$h_2=\dfrac{2,544}{20}$

$h_2=127.2\frac{KJ}{kg-m^2K}$

$So\ Percentage\ change=\dfrac{h_2-h_1}{h_1}\times 100$

$=\dfrac{127.2-120.3}{120.3}\times 100$

=5.75 %

So Percentage change 5.75 %.

3 0

2 years ago