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Artemon [7]
3 years ago
9

$600 a month on groceries, if this is 15% of the monthly budget, what is the monthly budget

Mathematics
2 answers:
Inessa05 [86]3 years ago
5 0

Answer:

$4,000

Step-by-step explanation:

.15x = $600

<u>.15x = $600.</u>  divide both sides by .15

.15.       .15

x = $4,000

Nataliya [291]3 years ago
4 0
4,000 if you set it up as unit rate with .15 on btm
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A nest of ants has been growing exponentially in such a way that it's population,P, as a function increasing on average more or
ivolga24 [154]

Not sure question is complete, assumptions however

Answer and explanation:

Given the above, the function of the population of the ants can be modelled thus:

P(x)= 1600x

Where x is the number of weeks and assuming exponential growth 1600 is constant for each week

Assuming average number of ants in week 1,2,3 and 4 are given by 1545,1520,1620 and 1630 respectively, then we would round these numbers to the nearest tenth to get 1500, 1500, 1600 and 1600 respectively. In this case the function above wouldn't apply, as growth values vary for each week and would have to be added without using the function.

On one hand, the function above could be used as an estimate given that 1600 is the average growth of the ants per week hence a reasonable estimate of total ants in x weeks can be made using the function.

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3 years ago
a gallon of milk contains 16 cups A pint of milk contains 2 cups . how many times. many cups are in a gallon than in a pint
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There are 16 cups in a gallon and 8 pints in a gallon
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3 years ago
Find the approximate area of the regions bounded by the curves y = x/(√x2+ 1) and y = x^4−x. (You may use the points of intersec
Finger [1]

The approximate area of the region bounded by the curves f(x) = x / √(x² + 1) and g(x) = x⁴ - x is approximately 0.806.

<h3>How to determine the approximate area of the regions bounded by the curves</h3>

In this problem we must use definite integrals to determine the area of the region bounded by the curves. Based on all the information given by the graph attached below, the area can be defined in accordance with this formula:

A = A₁ + A₂                                                                (1)

A₁ = ∫ [g(x) - f(x)] dx, for x ∈ [- 0.786, 0]                   (2)

A₂ = ∫ [f(x) - g(x)] dx, for x ∈ [0, 1.151]                       (3)

g(x) = x⁴ - x                                                               (4)

f(x) = x / √(x² + 1)                                                      (5)

Then, we proceed to find the integrals:

∫ g(x) dx = ∫ x⁴ dx - ∫ x dx = (1 / 5) · x⁵ - (1 / 2) · x²                          (6)

∫ f(x) dx = ∫ [x / √(x² + 1)] dx = (1 / 2) ∫ [2 · x / √(x² + 1)] dx = (1 / 2) ∫ [du / √u] = √u = √(x² + 1)                                                                                  (7)

And the complete expression for the integral is:

A = A₁ + A₂                                                                                      (1b)

A₁ = (1 / 5) · x⁵ - (1 / 2) · x² - √(x² + 1), for x ∈ [- 0.786, 0]               (2b)

A₂ = √(x² + 1) - (1 / 5) · x⁵ + (1 / 2) · x², for x ∈ [0, 1.151]                  (3b)

A₁ = 0.023

A₂ = 0.783

A = 0.023 + 0.783

A = 0.806

The approximate area of the region bounded by the curves f(x) = x / √(x² + 1) and g(x) = x⁴ - x is approximately 0.806.

To learn more on definite integral: brainly.com/question/14279102

#SPJ1

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Mashcka [7]
<span>4.4/1 * 10/10 = 44/10

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