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koban [17]
3 years ago
11

What is the equation of a line parallel to y= 7x-8 that passes through (5,-2)

Mathematics
2 answers:
Vinvika [58]3 years ago
6 0
General equation of line 
y = mx + c

Since this line is parallel to y=7x-8
m=7

y = 7x + c
If point (5,-2) is in that line,
-2 = (7*5) + c
-2 = 35 + c
c = -37

so the equation is
y = 7x + -37
k0ka [10]3 years ago
6 0
If the line is parallel, the slope is the same, but it's final term will be different. Since slope is the same, just go down 7 and left 1 from (5, -2) until you reach the y-axis, which will be at y=-9. This is your "b" term, since the equation is in y=mx+b form. So, your equation is y=7x-9.
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Answer:

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b. about 31.02 miles, rounded to 31 miles

Step-by-step explanation:

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81920/5280 = 15.51515151, rounded to the nearest tenth of a mile, 15.5 miles

Question b asks for how many miles in total has he ran. That means we have to add each of the values shown above and that equals to 163830 feet.

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Answer:

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Step-by-step explanation:

The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt

Comparing the standard form with the given differential equation.

p(t) = 1/t and q(t) = 3cos(2t)

I = e^∫1/tdt

I = e^ln(t)

I = t

The general solution for first a first order DE is expressed as;

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Integrating ∫t(cos2t)dt using integration by part.

Let u = t, dv = cos2tdt

du/dt = 1; du = dt

v = ∫(cos2t)dt

v = sin2t/2

∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt

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Substituting equation 2 into 1

yt = 3(tsin2t/2 - cos2t/4) + C

Divide through by t

y = 3sin2t/2 - 3cos2t/4t + C/t

Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t

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