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maxonik [38]
3 years ago
10

Does mercury have more protons and electrons than tin?

Chemistry
1 answer:
Eva8 [605]3 years ago
6 0
Yes. Mercury has 80 protons. Tin has 50 protons. Same for electrons, it just doesn't have an exact number.
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Given the following equation, what is the correct form of the conversion factor needed to convert the number of moles of O₂ to t
djverab [1.8K]

Answer : The correct option is (c) \frac{2\text{ mole of }Fe_2O_3}{3\text{ mole of }O_2}

Explanation :

The given balanced chemical reaction is,

4Fe(s)+3O_2(g)\rightarrow 2Fe_2O_3(s)

From the balanced chemical reaction, we conclude that

As, 3 moles of O_2 react to give 2 mole of Fe_2O_3

So, 1 mole of O_2 react to give \frac{2\text{ mole of }Fe_2O_3}{3\text{ mole of }O_2} moles of Fe_2O_3

Thus, the conversion factor needed to convert the number of moles of O_2 to the number of moles of Fe_2O_3 produced is \frac{2\text{ mole of }Fe_2O_3}{3\text{ mole of }O_2}

Hence, the correct option is (c) \frac{2\text{ mole of }Fe_2O_3}{3\text{ mole of }O_2}

7 0
3 years ago
Read 2 more answers
0.40 L of HNO3 is titrated to equivalence using 0.18 L of 0.1 M NaOH. What is the concentration of the HNO3 ?
e-lub [12.9K]

This problem is providing us with the volume of nitric acid that is titrated with 0.18 L of 0.1-M sodium hydroxide and asks for the concentration of the acid. At the end, the result turns out to be 0.045M, according to the following.

<h3>Acid-base titrations:</h3>

In chemistry, acid-base titrations allow us to quantify the volume or concentration of an acid or base via the following equation:

M_AV_A=M_BV_B

Where the subscript A stands for the acid and B for the base; which means one can calculate any of the variables there by knowing the other three. This equation is based on the balanced neutralization chemical equation, which takes place between the acid and the base.

Thus, we can write the reaction between NaOH and HNO3 as:

HNO_3+NaOH\rightarrow NaNO_3+H_2O

In such a way, we can solve for the concentration of the acid as shown below:

M_A=\frac{M_BV_B}{V_A} \\\\M_A=\frac{0.1M*0.18L}{0.40L} \\\\M_A=0.045M

Learn more about titration: brainly.com/question/25485091

3 0
2 years ago
Based on the ideal gas law, there is a simple equivalency that exists between the amount of gas and the volume it occupies. at s
nordsb [41]
<span>2.10 grams. The balanced equation for the reaction is CO + 2H2 ==> CH3OH The key thing to take from this equation is that it takes 2 hydrogen molecules per carbon monoxide molecule for this reaction. And since we've been given an equal number of molecules for each reactant, the limiting reactant will be hydrogen. We can effectively claim that we have 5.86/2 = 2.93 l of hydrogen and an excess of CO to consume all of the hydrogen. So the number of moles of hydrogen gas we have is: 2.93 l / 22.4 l/mol = 0.130803571 mol And since it takes 2 moles of hydrogen gas to make 1 mole of methanol, divide by 2, getting. 0.130803571 mol / 2 = 0.065401786 mol Now we just need to multiply the number of moles of methanol by its molar mass. First lookup the atomic weights involved. Atomic weight carbon = 12.0107 g/mol Atomic weight hydrogen = 1.00794 g/mol Atomic weight oxygen = 15.999 g/mol Molar mass CH3OH = 12.0107 + 4 * 1.00794 + 15.999 = 32.04146 g/mol So the mass produced is 32.04146 g/mol * 0.065401786 mol = 2.095568701 g And of course, properly round the answer to 3 significant digits, giving 2.10 grams.</span>
4 0
3 years ago
It takes a person 35 seconds to swim in a straight line from the east end of a pool to the west end of the pool, a distance of 5
viktelen [127]

Answer:

1.42m/s

Explanation:

velocity=displacement/time

v=50/35=1.42m/s

4 0
3 years ago
When a liquid is poured through a filter, what happens?
Anestetic [448]
The filter is a material with lots of tiny holes, that only the water can fit through. So flakes of leaf wont be in the water because it couldnt fit through the holes in the filter.

-.--.---./-------
The leaf flakes (periods) dont go through the filter (slash) but water (hiphens) does
4 0
3 years ago
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