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irinina [24]
3 years ago
6

According to the ph scale, which substance is the most basic?

Chemistry
1 answer:
Firlakuza [10]3 years ago
6 0
C sea water








l k. ,,.....................
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Explanation:

3 0
3 years ago
Read 2 more answers
What is the volume (in liters) occupied by 49.8 g og HCl at STP
Anon25 [30]

Using ideal gas equation,

P\times V=n\times R\times T

Here,

P denotes pressure

V denotes volume

n denotes number of moles of gas

R denotes gas constant

T denotes temperature

The values at STP will be:

P=1 atm

T=273 K

R=0.0821 atm L mol ⁻¹

Mass of HCl given= 49.8 g

Molar mass of HCl given=36.41

Number of moles of gas, n= \frac{Given mass of the substance}{Molar mass of the substance}

Number of moles of gas, n= \frac{49.8}{36.46}

Number of moles of gas, n= 1.36

Putting all the values in the above equation,

V=\frac{1.36\times 0.0821\times 273}{1}

V=30.6 L

So the volume will be 30.6 L.



6 0
2 years ago
What volume (in liters) does 3.91 moles of nitrogen gas at 5.35 atm and 323 K occupy
daser333 [38]
Moles   =  n  = 3.91 mol

                  Pressure  =  P  =  5.35 atm

                  Temperature  =  T  =  323 K

                  Volume  =  V  =  ?

Formula used: Ideal Gas Equation is used,

                                        P V  = n R  T
Solving for V,
                                           V  =  n R T / P
Putting Values,
                           V  =  (3.91 mol × 0.0825 atm.L.mol⁻¹.K⁻¹ × 323 K) ÷ 5.35 atm

                         V  =  19.36 L

5 0
3 years ago
Calcula la densidad de un cuerpo que tiene la masa de 12g y un volumen de 3cm^3 dar el resultado en unidades del SI
kvv77 [185]

The density is 4 g/cm³ or 4000 kg/m³.

Density = mass/volume = 12 g/3 cm³ = 4 g/cm³

The measurement of 4 g/cm³ is already in <em>SI units</em>.  

In SI <em>bas</em>e units,  

Density = (4 g/1 cm³) × (1 kg/1000 g) × (100 cm/1 m)³ = 4000 kg/m³


3 0
3 years ago
If 4.0 g of hydrogen and 10.0 g of oxygen are mixed according to the equation 2 h2 + o2 → 2 h2o, which is the limiting reagent?
mars1129 [50]
From the equation, we can see that the molar ratio between hydrogen and oxygen is:
2 : 1

Next, we determine the moles of hydrogen and oxygen that are actually present using:
moles = mass / Mr

Hydrogen:
moles = 4 / 2 = 2

Oxygen:
10/32 = 0.3125

Therefore, it is evident that the moles of oxygen present, 0.3125, are less than those that are required for 2 moles of hydrogen, which is 1. This makes oxygen the limiting reactant, which is the one that limits the completion of a reaction.
8 0
3 years ago
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