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Katarina [22]
4 years ago
6

Be sure to answer all parts. identify and label the species in each reaction. (a) nh4+(aq) + h2o(l) ⇌ nh3(aq) + h3o+(aq) acid ba

se acid base conjugate acid conjugate base conjugate acid conjugate base (b) cn−(aq) + h2o(l) ⇌ hcn(aq) + oh−(aq) acid base acid base conjugate acid conjugate base conjugate acid conjugate base
Chemistry
1 answer:
quester [9]4 years ago
5 0
A)

NH⁴⁺(aq) + H₂O(l) ⇌ NH₃(aq) + H₃0⁺<span>(aq)

- acid </span>a species that able to donate (H+): NH⁴⁺
- base a species that is able to accept a proton (H+): H₂O
- conjugate base a species formed when acid donates a proton (H+): NH₃
- conjugate acid a species formed by a base accepts a proton (H+): H₃0⁺

b)

CN⁻(aq) + H₂O(l) ⇌ HCN(aq) + OH⁻(aq)

- base a species that is able to accept a proton (H+): CN⁻
- acid a species that able to donate (H+): H₂O
- conjugate acid a species formed by a base accepts a proton (H+): HCN
- conjugate base a species formed when acid donates a proton (H+): OH⁻

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A 25.0-mL sample of 0.150 M butanoic acid is titrated with a 0.150 M NaOH solution. What is the pH before any base is added? The
hoa [83]
HA ⇄ H⁺ + A⁻ 
so:
\frac{[H^+][A^-]}{[HA]} = 1.5 x 10^{-5}
and now:
\frac{(x)(x)}{(0.150-x)} = 1.5 x 10⁻⁵
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7 0
3 years ago
If 0.8 g of gas Z occupies 0.56 dm at s.1.p., calculate its relative molecular mass. (Molar volume of gas is 22.4 dm.)​
photoshop1234 [79]

Answer:

32

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0.56dm of gas has 0.8g

22.4dm of gas Z has a mass of 22.4/0.56X0.8

the relative molecular mass of gas Z is 32

8 0
3 years ago
A 7.00-mL portion of 8.00 M stock solution is to be diluted to 0.800 M. What will be the final volume after dilution? Enter your
amm1812

Explanation:

The number of moles of solute present in liter of solution is defined as molarity.

Mathematically,         Molarity = \frac{\text{no. of moles}}{\text{Volume in liter}}

Also, when number of moles are equal in a solution then the formula will be as follows.

                     M_{1} \times V_{1} = M_{2} \times V_{2}

It is given that M_{1} is 8.00 M, V_{1} is 7.00 mL, and M_{2} is 0.80 M.

Hence, calculate the value of V_{2} using above formula as follows.

                    M_{1} \times V_{1} = M_{2} \times V_{2}

                 8.00 M \times 7.00 mL = 0.80 M \times V_{2}

                      V_{2} = \frac{56 M. mL}{0.80 M}

                                  = 70 ml

Thus, we can conclude that the volume after dilution is 70 ml.

7 0
3 years ago
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