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3 years ago

In your own words, what is conduction

1 answer:

8 0

Heat conduction or energy transfer in the form of heat by conduction is a process of heat transmission based on direct contact between bodies, without material exchange

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What property of matter do we consider when deciding whether to buy a half-gallon of milk at the store versus a gallon of milk?

Mrac [35]

Liquified matter maybe.

7 0

3 years ago

Two satellites, X and Y, are orbiting Earth. Satellite X is 1.2 × 106 m from Earth, and Satellite Y is 1.9 × 105 m from Earth. W

jenyasd209 [6]

Answer: Satellite X has a greater period and a slower tangential speed than Satellite Y

Explanation:

According to Kepler’s Third Law of Planetary motion “The square of the orbital period of a planet is proportional to the cube of the semi-major axis (size) of its orbit”.

$T^{2}=\frac{4\pi^{2}}{GM}r^{3}$ (1)

Where;

$G=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}$ is the Gravitational Constant

$M=5.972(10)^{24}kg$ is the mass of the Earth

$r$ is the semimajor axis of the orbit each satellite describes around Earth (assuming it is a circular orbit, the semimajor axis is equal to the radius of the orbit)

So for satellite X, the orbital period $T_{X}$ is:

$T_{X}^{2}=\frac{4\pi^{2}}{GM}r_{X}^{3}$ (2)

Where $r_{X}=1.2(10)^{6}m$

$T_{X}^{2}=\frac{4\pi^{2}}{(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}})(5.972(10)^{24}kg)}(1.2(10)^{6}m)^{3}$ (3)

$T_{X}=413.712 s$ (4)

For satellite Y, the orbital period $T_{Y}$ is:

$T_{Y}^{2}=\frac{4\pi^{2}}{GM}r_{Y}^{3}$ (5)

Where $r_{Y}=1.9(10)^{5}m$

$T_{Y}^{2}=\frac{4\pi^{2}}{(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}})(5.972(10)^{24}kg)}(1.9(10)^{5}m)^{3}$ (6)

$T_{Y}=26.064 s$ (7)

This means $T_{X}>T_{Y}$

Now let's calculate the tangential speed for both satellites:

<u>For Satellite X:</u>

$V_{X}=\sqrt{\frac{GM}{r_{X}}}$ (8)

$V_{X}=\sqrt{\frac{(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}})(5.972(10)^{24}kg)}{1.2(10)^{6}m}}$

$V_{X}=18224.783 m/s$ (9)

<u>For Satellite Y:</u>

$V_{Y}=\sqrt{\frac{GM}{r_{Y}}}$ (10)

$V_{Y}=\sqrt{\frac{(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}})(5.972(10)^{24}kg)}{1.9(10)^{5}m}}$

$V_{Y}= 45801.13 m/s$ (11)

This means $V_{Y}>V_{X}$

Therefore:

Satellite X has a greater period and a slower tangential speed than Satellite Y

4 0

3 years ago

Read 2 more answers

A T-bar tow is required to pull 85 skiers up a 600 m slope inclined at 15° above horizontal at a speed of 2.5 m/s. The coefficie

dalvyx [7]

Answer:

P = 1.45 hp or 1.94kW

Explanation:

Given:

v = 2.5m/s

uk = 0.06

m = 60kg

Fk = uk*m*g*fsin(15)

Fk = 0.06*85*9.81*60*sin(15)

Fk = 776.15 N

Power=force*speed

P = F*v

P = 776.15N*2.5m/s

P = 1940.36 W

1 Horsepower = 0.7457 Kilowatts

P = 1.45 hp

5 0

4 years ago

A football player kicks a 0.94 kg football with a force of 2.4 N.

Artyom0805 [142]

2.6m/s²

Explanation:

Given parameters:

Mass of football = 0.94kg

Force on ball = 2.4N

Unknown:

The acceleration of the ball = ?

Solution:

According to Newton's second law of motion "the net force on a body is the product of its mass and acceleration".

Net force = mass x acceleration

Make acceleration the subject of the expression;

Acceleration = $\frac{net force}{mass}$

Acceleration = $\frac{2.4}{0.94}$ = 2.6m/s²

learn more:

Acceleration brainly.com/question/3820012

#learnwithBrainly

6 0

3 years ago

Read 2 more answers

Which type of lens will produce a virtual image

Naily [24]

When a object is close to the converging lens it behaves like a magnifying glass. Therefore convex mirror produces a virtual image. A real image occurs when a ray converges, whereas virtual image occurs when rays only Appear to converge.

7 0

3 years ago