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Anastaziya [24]
3 years ago
5

A T-bar tow is required to pull 85 skiers up a 600 m slope inclined at 15° above horizontal at a speed of 2.5 m/s. The coefficie

nt of kinetic friction is 0.06. Find the motor power required if the mass of the average skier is 60 kg.
Physics
1 answer:
dalvyx [7]3 years ago
5 0

Answer:

P = 1.45 hp or 1.94kW

Explanation:

Given:

v = 2.5m/s

uk = 0.06

m = 60kg

Fk = uk*m*g*fsin(15)

Fk = 0.06*85*9.81*60*sin(15)

Fk = 776.15 N

Power=force*speed

P = F*v

P = 776.15N*2.5m/s

P = 1940.36 W

1 Horsepower = 0.7457 Kilowatts

P = 1.45 hp

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IceJOKER [234]

Answer:

Explanation:

Given that,

First Capacitor is 10 µF

C_1 = 10 µF

Potential difference is

V_1 = 10 V.

The charge on the plate is

q_1 = C_1 × V_1 = 10 × 10^-6 × 10 = 100µC

q_1 = 100 µC

A second capacitor is 5 µF

C_2 = 5 µF

Potential difference is

V_2 = 5V.

Then, the charge on the capacitor 2 is.

q_2 = C_2 × V_2

q_2 = 5µF × 5 = 25 µC

Then, the average capacitance is

q = (q_1 + q_2) / 2

q = (25 + 100) / 2

q = 62.5µC

B. The two capacitor are connected together, then the equivalent capacitance is

Ceq = C_1 + C_2.

Ceq = 10 µF + 5 µF.

Ceq = 15 µF.

The average voltage is

V = (V_1 + V_2) / 2

V = (10 + 5)/2

V = 15 / 2 = 7.5V

Energy dissipated is

U = ½Ceq•V²

U = ½ × 15 × 10^-6 × 7.5²

U = 4.22 × 10^-4 J

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U = 422 µJ

6 0
4 years ago
When a 0.292 kg mass on a string is swung at 8.45 m/s, it feels a centripetal acceleration of 78.9 m/s^2. What is the radius of
miss Akunina [59]

Answer:

r=0.26m

Explanation:

F=mv^2/r

78.9=0.292*(8.45)^2/r

r=0.292*(8.45)^2/78.9

r=0.26m

3 0
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ahrayia [7]

Answer:

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Explanation:

The masses of the cars with their respective initial velocities are;

m_1 = 212kg

u_1 = 8.00 m{s}^{ - 1}

m_2 = 196kg

u_1 =6.75m {s}^{ - 1}

Since the two car stuck after collision, they all move with a common velocity in the same direction.

Let the velocity at which the two cars will be moving after collision be V.

From the conservation of momentum, in a closed system, momentum before collision is equal to momentum after collision.

Mathematically,

m_1u_1 +m_2u_2 = (m_1 + m_2)v

By substitution, we obtain;

(212 \times 8) +(196 \times 6.75) = (212 + 196)v

\implies1696+1323 =408 \times v

\implies3019 =408 \times v

Dividing through by 408, we obtain

\implies\frac{3019}{408} =  \frac{408 \times v }{408}

\implies v =7.3995

Therefore,v=7.40m/s

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Answer:

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Answer:

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