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3 years ago

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1. A rectangular fish tank measures 1.5 meters by 2 meters by 20 cm. When it is filled with water, how many kilograms will the w

ater in the tank weigh?

1 answer:

chubhunter [2.5K]3 years ago

7 0

20kg I’m pretty sure

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A freeway is being designed for a location in rolling terrain. The expected free-flow speed is 55 mi/h. During the peak hour, it

balu736 [363]

Answer:

3.

Explanation:

We start calcualting the factor for heavy-vehicle, that is,

$f_{HV} = \frac{1}{1+P_T(E_T-1)+P_R(E_R-1)}$

$E_T = 2.5$ for rolling terrain, so, replacing,

$f_{HV} = \frac{1}{1+0.18(2.5-1)+0}$

$f_{HV} = 0.7874$

We calculate the number of lanes by using the relation as follow:

$N=\frac{V}{\upsilon_p PHF f_{HV} f_p}$

$N=\frac{2700}{1915*0.88*0.7874*1}$

$N= 2.035$

In this way the necessary number of lanes is 3.

Note: To calculate $\upsilon_p$ you need to consult the Exhibit 23-2

in 'Highway capacity Manual' for 55mph and the LOS D criteria.

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4 years ago

What are things that need to be considered with respect to the environment when design and construction is occurring?

Law Incorporation [45]

Answer:

If you are destroying the environment or habitats or trees. Also if people live nearby. Also if its legal.

Explanation:

8 0

3 years ago

The Bureau of Labor and Statistics predicted that the field of biomedical engineering would increase by 62 percent over the comi

raketka [301]

Answer:

C. It is a continually growing field, and individuals trained in it should not have a problem finding employment.

Explanation:

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3 years ago

A hollow steel cylinder with an outside diameter of 100 mm is required to carry a tensile load of 500 kN. Given that the allowab

ivolga24 [154]

Answer:

Maximum inside diameter is 68.52 mm.

Explanation:

Apply stress formula to calculate inside diameter of the tube. Take the allowable stress for safe design and maximum inside diameter of the steel tube.

Step1

Given:

Outside diameter is 100 mm.

Tensile load is 500 kN.

Allowable stress is 120 Mpa.

Calculation:

Step2

Inside diameter is calculated by the stress formula as follows:

$\sigma_{a}=\frac{F}{A}$

$\sigma_{a}=\frac{F}{\frac{\pi}{4}(d_{o}^{2}-d_{i}^{2})}$

$120=\frac{500\times1000}{\frac{\pi}{4}(100^{2}-d_{i}^{2})}$

$(100^{2}-d_{i}^{2})=5305.164$

$d_{i}=68.52$ mm

Thus, the inner diameter is 68.52 mm.

6 0

3 years ago

Air modeled as an ideal gas enters a combustion chamber at 20 lbf/in.2

motikmotik

Answer:

The answer is " $112.97 \ \frac{ft}{s}$ "

Explanation:

Air flowing into the $p_1 = 20 \ \frac{lbf}{in^2}$

Flow rate of the mass $m = 230.556 \frac{lbm}{s}$

inlet temperature $T_1 = 700^{\circ} F$

Pipeline $A= 5 \times 4 \ ft$

Its air is modelled as an ideal gas Apply the ideum gas rule to the air to calcule the basic volume v:

$\to \bar{R} = 1545 \ ft \frac{lbf}{lbmol ^{\circ} R}\\\\ \to M= 28.97 \frac{lb}{\bmol}\\\\ \to pv=RT \\\\\to v= \frac{\frac{\bar{R}}{M}T}{p}$

$= \frac{\frac{1545}{28.97}(70^{\circ}F+459.67)}{20} \times \frac{1}{144}\\\\=9.8 \frac{ft3}{lb}$

$V= \frac{mv}{A}$

$= \frac{230.556 \frac{lbm}{s} \times 9.8 \frac{ft^3}{lb}}{5 \times 4 \ ft^2}\\\\= 112.97 \frac{ft}{s}$

8 0

3 years ago