Answer:
a)
1) R16C ; Tn = 17 TMU
2) G4A ; Tn = 7.3 TMU
3) M10B5 ; Tn = 15.1 TMU
4) RL1 ; Tn = 2 TMU
5) R14B ; Tn = 14.4 TMU
6) G1B ; Tn = 3.5 TMU
7) M8C3 ; Tn = 14.7 TMU
8) P1NSE ; Tn = 10.4 TMU
9) RL1 ; Tn = 2 TMU
b) 3.1 secs
Explanation:
a) Determine the normal times in TMUs for these motion elements
1) R16C ; Tn = 17 TMU
2) G4A ; Tn = 7.3 TMU
3) M10B5 ; Tn = 15.1 TMU
4) RL1 ; Tn = 2 TMU
5) R14B ; Tn = 14.4 TMU
6) G1B ; Tn = 3.5 TMU
7) M8C3 ; Tn = 14.7 TMU
8) P1NSE ; Tn = 10.4 TMU
9) RL1 ; Tn = 2 TMU
b ) Determine the total time for this work element in seconds
first we have to determine the total TMU = ∑ TMU = 86.4 TMU
note ; 1 TMU = 0.036 seconds
hence the total time for the work in seconds = 86.4 * 0.036 = 3.1 seconds
The true statement about the dot plot is 1 has 4 and 0 dots.
Explanation:
- after creating a Bar chart 4 is the right answer.
- The highest among st all the other plots is 1 but 4 shows 3.
- Taking an average from all the data points 3 comes to the right answer.
- Median the central Mid-point is 3.
- Mode also comes to 3.
- It is skewed on the right due to the 1st one.
- Skewed shows the data point either increasing or in decreasing.
- There a to Bi- histograms which has two ups and downs.
- The true statement has to be as Mean=Median=Mode is 3.
Answer:
#include <stdio.h>
typedef struct InventoryTag_struct {
int itemID;
int quantityRemaining;
} InventoryTag;
int main(void) {
InventoryTag redSweater;
redSweater.itemID = 314;
redSweater.quantityRemaining = 500;
/* Your solution goes here */
printf("Inventory ID: %d, Qty: %d\n",redSweater.itemID,redSweater.quantityRemaining);
getchar();
return 0;
}
Explanation: