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Mariana [72]
3 years ago
13

What are the most used electronic tools for electronic works?​

Engineering
1 answer:
Zanzabum3 years ago
6 0

Answer:

  • Needle-nose pliers.
  • Hemostats.
  • A spool of 30-gauge wire.
  • A spool of solder wick.
  • A spool of solder.
  • A loupe.
  • Three sets of tweezer

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Un MOSFET de potencia es un dispositivo de?
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Los MOSFET de potencia son dispositivos de conducción unipolar. En ellos, los niveles de corriente conducida no están asociados al aumento de la concentración de portadores minoritarios, que luego son difíciles de eliminar para que el dispositivo deje de conducir.
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Illustrate the crowbar protection for silicon controlled rectifier​
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The SCR over voltage crowbar or protection circuit is connected between the output of the power supply and ground. ... It also clamps the gate voltage at ground potential until the Zener turns on. The capacitor C1 is present to ensure that short spikes to not trigger the circuit.

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Jump starting a car requires _____.
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Lb(force)•second/ft^2
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4 years ago
Determine the speed of sound in air at 400 K. Also determine the Mach number of an aircraft moving in the air at a velocity of 3
Reika [66]

Answer:

\alpha = \sqrt{1.4 *0.287 \frac{KJ}{Kg K}*\frac{1000J}{1KJ} *400 K}= 400.899 m/s

Ma= \frac{310 m/s}{400.899 m/s}= 0.773

Explanation:

For this case we have given the following data:

T= 400 K represent the temperature for the air

v = 310 m/s represent the velocity of the air

k = 1.4 represent the specific heat ratio at the room

R = 0.287 KJ/ Kg K represent the gas constant  for the air

And we want to find the velocity of the air under these conditions.

We can calculate the spped of the sound with the Newton-Laplace Equation given by this equation:

\alpha = \sqrt{\frac{K}{\rho}}=\sqrt{k RT}

Where K = is the Bulk Modulus of air, k is the adiabatic index of air= 1.4, R = the gas constant  for the air, \rho the density of the air and T the temperature in K

So on this case we can replace and we got:

\alpha = \sqrt{1.4 *0.287 \frac{KJ}{Kg K}*\frac{1000J}{1KJ} *400 K}= 400.899 m/s

The Mach number by definition is "a dimensionless quantity representing the ratio of flow velocity past a boundary to the local speed of sound" and is defined as:

Ma=\frac{v}{\alpha}

Where v is the flow velocity and \alpha the volocity of the sound in the medium and if we replace we got:

Ma= \frac{310 m/s}{400.899 m/s}= 0.773

And since the Ma<0.8 we can classify the regime as subsonic.

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