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Licemer1 [7]
3 years ago
13

What is the gravitational acceleration on which a 2-kilogram mass has a weight of 16 Newton's?

Physics
1 answer:
Step2247 [10]3 years ago
5 0

Answer:8 m/s ^2

Explanation:

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Why earth have gravity​
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Answer:

Because it has mass.

Explanation:

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Answer and explanation please!! ​
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Answer:

Option 3

Explanation:

O Option C is NEGATIVELY CHARGED, meaning it has GAINED ELECTRONS resulting in a GREATER number of ELECTRONS than PROTONS.

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Divers in Acapulco dive from a cliff that is 65 m high. If the rocks
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3 years ago
There are 8.8 liters of gas in a piston at a pressure of 1.75 atmospheres. The temperature remains constant, and the gas is comp
saveliy_v [14]

The new pressure P2 is 2.48 atmosphere.

<u>Explanation:</u>

Here, the one of the product of pressure and volume is equal to the products of pressure and volume of other.

By using Boyles's law,

               pressure is inversely proportional to volume,

                                         P1 V1 = P2 V2

where P1, V1 represents the first pressure and volume,

           P2, V2 represents the second pressure and volume

                                              P2 = (P1 V1) / V2

                                                    = (1.75 \times 8.8) / 6.2

                                              P2  = 2.48 atmosphere.  

         

5 0
3 years ago
4. Going back to the dog whistle in question 1, what is the minimum riding speed needed to be able to hear the whistle? Remember
jeyben [28]

Answer:

The minimum riding speed relative to the whistle (stationary) to be able to hear the sound at 21.0 kHz frequency is 15.7  m/s

Explanation:

The Doppler shift equation is given as follows;

f' = \dfrac{v - v_o}{v + v_s} \times f

Where:

f' = Required observed frequency = 20.0 kHz

f = Real frequency = 21.0 kHz

v = Sound wave velocity = 330 m/s

v_o = Observer velocity = X m/s

v_s = Source velocity = 0 m/s (Assuming the source is stationary)

Which gives;

20 = \dfrac{330- v_o}{330+0} \times 21

330 - v_o = (20/21)*330

v_o = 330 - (20/21)*330 = 15.7 m/s

The minimum riding speed relative to the whistle (stationary) to be able to hear the sound at 21.0 kHz frequency = 15.7  m/s.

8 0
3 years ago
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