Answer:
Mercury
Explanation:
Mercury is a liquid element that contains 80 electrons when not charged.
Answer:
C₅H₈NO₄Na
Explanation:
Step 1: Given data
- Percentage by mass of Na in MSG: 13.6%
- Percentage by mass of C in MSG: 35.5%
- Percentage by mass of H in MSG: 4.8%
- Percentage by mass of N in MSG: 8.3%
- Percentage by mass of O in MSG: 37.8%
Step 2: Divide each percentage by the atomic mass of the element
Na: 13.6/22.99 = 0.592
C: 35.5/12.01 = 2.96
H: 4.8/1.01 = 4.75
N: 8.3/14.00 = 0.592
O: 37.8/16.00 = 2.36
Step 3: Divide all the number by the smallest one, i.e. 0.592
Na: 0.592/0.592 = 1
C: 2.96/0.592 = 5
H: 4.75/0.592 ≈ 8
N: 0.592/0.592 = 1
O: 2.36/0.592 ≈ 4
The empirical formula of MSG is C₅H₈NO₄Na.
Uruk was much larger with a large population, people practiced customs and government that included kings
Step one write the chemical equation for reaction
= Ag2O + 2(C10H10N4SO2)---> 2 ( AgC10H9N4SO2)
The reacting ratio of Ag2O to AgC10H9N4SO2 is 1:2 from the reaction above
step 2; find the number of moles of AgC10H9N4SO2
that is mass/molar mass
The molar mass of AgC10H9N4SO2 = 107.86 +(12 x10) + (1 x 9) + (4 x 14) +32 +(16 x2) =356.86g/mol
moles is therefore= 25g/356.86g/mol= 0.07moles
by use of mole ratio the moles of Ag2O= 0.0702=0.035moles
mass = moles x molar mass
the molar mass of Ag2O=231.72 g/mol
mass is therefore= 231.72g/mol x 0.035moles= 8.11grams
Answer: -
Molality of NaCl = 2.807 ×10⁻² m
Explanation: -
Molarity given = 2.800×10⁻² M
This means there are 2.800×10⁻² moles of NaCl per 1000 mL of solution.
Volume of water = 999.2 ml
Density of water = 0.9982 g/ml
Mass of water = Density of water x Volume of water
= 0.9982 g/ml x 999.2 ml
= 997.4 g
Thus 997.4 g of water has 2.800×10⁻² moles of NaCl.
1000 g of water has x 2.800×10⁻² moles of NaCl.
= 2.807 ×10⁻² moles of NaCl.
Molality of NaCl = 2.807 ×10⁻² m