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Vikki [24]
3 years ago
6

What is the acceleration of a 31 kg object pushed with a force of 42N

Physics
1 answer:
Ray Of Light [21]3 years ago
3 0
I belive it could be 6.5 but I could be wrong
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10. A force F S 1 of magnitude 6.00 units acts on an object at the ori- gin in a direction u 5 30.0° above the positive x axis (
MArishka [77]

Answer:

The x component of the x axis is:   F_x = F_1\cos(30)=5\cos(30)= 4.33 u

The y component of the y axis is:  F_y =F_2+ F_1\sin(30)=6.00+5\sin(30)= 8.50 u

The magnitude is given by:  F = \sqrt{F_x+F_y}= 9.54 u

The direction is given by:  \theta = \tan^{-1}\frac{F_y}{F_x}= 63.0 ^\circ

See the graphical magnitude and direction below.

Explanation:

The x component of the x axis is:   F_x = F_1\cos(30)=5\cos(30)= 4.33 u

The y component of the y axis is:  F_y =F_2+ F_1\sin(30)=6.00+5\sin(30)= 8.50 u

The magnitude is given by:  F = \sqrt{F_x+F_y}= 9.54 u

The direction is given by:  \theta = \tan^{-1}\frac{F_y}{F_x}= 63.0 ^\circ

8 0
3 years ago
You are in a car and go around a corner very fast. What happens to you?
Fiesta28 [93]

Answer:

You may tip the car over or crash.

Explanation:

Going really fast at high speeds and turn a corner might make the car crash into an object or fall over.

3 0
3 years ago
A solid object has a mass of 104 kg and a volume of 1,278 m3. What is its density? 0.081 kg/m3 12.29 g/cm3 132912.00 g/cm3 canno
REY [17]
The density is 81.4 g/m3. Before you start plugging numbers into the density formula (D=M/V), you should convert 104 kg to grams, which ends up being 104,000 grams. Then you can plug in the 104,000 grams and 1,278 m3 into the formula. When you divide the mass by the volume, you get a really long decimal, which you can round to 81.4 g/m3, or whatever place your teacher wants you to round to.
4 0
3 years ago
Read 2 more answers
A disk is uniformly accelerated from rest with angular acceleration α. The magnitude of the linear acceleration of a point on th
solniwko [45]

Answer:

a = R\alpha\sqrt{1 + \alpha^2t^4}

Explanation:

As we know that the acceleration of a point on the rim of the disc is in two directions

1) tangential acceleration which is given as

a_t = R\alpha

2) Centripetal acceleration

a_c = \omega^2 R

here we know that

\omega = \alpha t

a_c = (\alpha t)^2 R

now we know that net linear acceleration is given as

a = \sqrt{a_c^2 + a_t^2}

so we have

a = \sqrt{R^2\alpha^2 + R^2(\alpha t)^4}

a = R\alpha\sqrt{1 + \alpha^2t^4}

4 0
3 years ago
Sea floor spreading could produce A) an ocean B) a mountain range C) a volcano D) a single fault-block mountain
lesya692 [45]
I think it is A. An Ocean
5 0
3 years ago
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