Explanation A 5000 kg rocket is at rest in deep space. The rocket burns fuel pushing 10kg of exhaust gases rearward at 4000 m/s.
 This process takes 10 s. During the time interval what average force is applied to the rocket?
       
      
                
     
    
    
    
    
    2 answers:
            
              
              
                
                
Answer:
F = 4000 N
Explanation:
given,
mass of rocket (M)= 5000 Kg
10 Kg gas burns at speed (m)= 4000 m/s
time = 10 s
average force = ?
at the end the rocket is at rest
by conservation of momentum
  M v + m v' = 0
  5000 x v - 10 x 4000 = 0
  5000 v = 40000
     v = 8 m/s
speed of rocket = 8 m/s
 now,
 we know
 change in momentum = F x Δ t
 

       F = 4000 N
Hence, the average force applied to the rocket is equal to F = 4000 N
 
 
                                
             
                    
              
              
                
                
Answer:
4000 N 
Explanation:
mass of fuel, m = 10 kg 
velocity of ejected fuel, v = 4000 m/s 
time, t = 10 s 
force, F = velocity x mass of fuel burning per second 
F = 4000 x 10 / 10 = 4000 N 
Thus, the force is 4000 N. 
 
                                
             
         	    You might be interested in
    
        
        
Answer:
2.5
Explanation:2.5 +2.5 = 5.0
 
        
             
        
        
        
Answer:
the formula is efficiency = output / input × 100%
 
        
             
        
        
        
I think yes because you won’t be able to smell
        
             
        
        
        
Answer:
destroys habitats is the main one
Explanation:
eye sore can be one and it can burst causing a flood is also one :)
 
        
                    
             
        
        
        
Does it give you options?