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likoan [24]
3 years ago
11

Which statement is correct

Physics
1 answer:
daser333 [38]3 years ago
8 0

C Weight is the gravitational pull on an object

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Describe how the resistance of the filament lamp changes as the current through it increases.
pochemuha
This heats up when an electric current passes through it, and produces light as a result. The resistance of a lamp increases as the temperature of its filament increases. The current flowing through a filament lamp is not directly proportional to the voltage across it.
8 0
3 years ago
A 4.55 nF parallel-plate capacitor contains 27.5 μJ of stored energy. By how many volts would you have to increase this potentia
aivan3 [116]

Answer:

\Delta V=V_{2}-V_{1}=45.4V

Explanation:

The energy, E, from a capacitor, with capacitance, C, and voltage V is:

E=\frac{1}{2} CV^{2}

V=\sqrt{2E/C}

If we increase the Voltage, the Energy increase also:

V_{1}=\sqrt{2E_{1}/C}

V_{2}=\sqrt{2E_{2}/C}

The voltage difference:

V_{2}-V_{1}=\sqrt{2E_{2}/C}-\sqrt{2E_{1}/C}

V_{2}-V_{1}=\sqrt{2*55*10^{-6}/4.55*10^{-9}}-\sqrt{2*27.5*10^{-6}/4.55*10{-9}}=45.4V

5 0
3 years ago
The equation for the speed of an electromagnetic wave is
igomit [66]

Answer:

c = 1 / √(ε₀*μ₀)

Explanation:

The speed of the electromagnetic wave in free space is given in terms of the permeability and the permittivity of free space by

c = 1 / √(ε₀*μ₀)

where the permeability of free space (μ₀) is a physical constant used often in electromagnetism and ε₀ is the permittivity of free space (a physical constant).

4 0
3 years ago
A circuit is shown in the picture above. The chemical energy in the battery is used to light up the light bulb on the other end.
Ainat [17]
To be honest, the picture is so far above that I can't see it at all.
But reading the information in the question's statement, I'd say
the blank should be filled in so that it says:

<span>   The chemical energy in the battery is used to light up the light bulb
   on the other end. Chemical energy in the battery is transformed into
   electrical energy which runs through the circuit wire. (A)</span>
8 0
4 years ago
Read 2 more answers
Estimate (a) the maximum, and (b) the minimum thermal conductivity values (in W/m-K) for a cermet that contains 83 vol% carbide
velikii [3]

Answer:

  k_max = 31.82 w/mk

  k_min  = 17.70 w/mk

Explanation:

a) the maximum thermal conductivity is given as

k_{max} = k_m*v_m + k_p*v_p

where k_m is thermal conductvitiy of metal

k_p is thermal conductvitiy of carbide

v_m = proportion of metal in the cement = 0.17

v_p = proportion of carbide in the cement = 0.83

            = 66*0.17 + 28*0.83

           k_max = 31.82 w/mk

b) the minimum thermal conductivity is given as

k_{min} = \frac{k_{carbide}* k_{metal}}{k_{metal} v_{carbide} +k_{metal} v_{carbide}}

          = \frac{28+66}{28*0.17 +66*0.83}

       k_min  = 17.70 w/mk

7 0
3 years ago
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