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Karo-lina-s [1.5K]
3 years ago
8

An electrician is creating a wiring plan for a small house. He needs to create a plan that will allow the homeowners to turn off

lights in one room without turning off the lights in another. What should he do to assure that each room's lights function independently of one another?
A) He should wire each room in series with the next.
B) He should wire each room in parallel with the next.
C) He should make sure each room's lights provide the same resistance.
D) He should wire the room with the most lights directly to the circuit breaker box.
Physics
2 answers:
Naily [24]3 years ago
8 0
So the answer is B) he should wire each room in parallel. This is because when the bulbs are in parallel if one part of the parallel circuit is broken (eg when you switch a light off) then the current can still flow to all the other bulbs, meaning they stay turned on. Hope this helps :)
Anika [276]3 years ago
8 0

Answer:

the answer is B

Explanation:

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A rubber ball and a lump of clay have equal mass. They are thrown with equal speed against a wall. The ball bounces back with ne
gregori [183]

Answer:

The ball experiences the greater momentum change

Explanation:

The momentum change of each object is given by:

\Delta p = m \Delta v= m (v-u)

where

m is the mass of the object

v is the final velocity

u is the initial velocity

Both objects have same mass m and same initial velocity u. So we have:

- For the ball, the final velocity is

v=-u

Since it bounces back (so, opposite direction --> negative sign) with same speed (so, the magnitude of the final velocity is still u). So the change in momentum is

\Delta p=m(v-u)=m((-u)-u)=-2mu

- For the clay, the final velocity is

v=0

since it sticks to the wall. So, the change in momentum is

\Delta p = m(v-u)=m(0-u)=-mu

So we see that the greater momentum change (in magnitude) is experienced by the ball.

3 0
3 years ago
The following force diagram represents Newton’s Third Law of Motion:
Julli [10]

Answer:

<u>FALSE.</u>

Explanation:

Newton's third law states that :

  • <em>Every action has equal and opposite reaction</em>
  • <em>That is , the magnitude is the same but the directions are opposite</em>
  • <em>The action reaction forces DONOT operate on the same body.</em>

For example ,

If a block is kept on the ground , the action force is the normal force acting on it due to the ground. <em>BUT , NOTE THAT : the reaction force isn't the gravitational force on the body ! It is the normal force acting on the ground due to the block !</em>

Thus,

we conclude that action and reaction forces donot act on the same body and therefore , this case has the <u>answer : FALSE </u>

4 0
3 years ago
Weightlessness is experienced by an astronaut in space. This means that the astronaut's muscles have to be stronger to move his
just olya [345]
The answer is false. The speed of the astronaut cancels out the force of gravity, causing a 'stationary freefall'. While under these effects, it is not required for an astronaut to 'strengthen' his body.
4 0
3 years ago
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Two scientists are discussing their beliefs about something they cannot observe
svetoff [14.1K]
Could it be hypothesis?
5 0
2 years ago
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Two particles with oppositely signed charges are held a fixed distance apart. The charges are equal in magnitude and they exert
damaskus [11]

Answer:

the force will decrease to 3/4 of its original value.

Explanation:

The initial electric force between the two charges is:

F = k \frac{q\cdot q}{r^2}

where

k is the Coulomb's constant

q is the magnitude of each charge

r is their separation

Later, half of one charge is transferred to the other charge; this means that one charge will have a charge of

q+\frac{q}{2}=\frac{3}{2}q

while the other charge will be

q-\frac{q}{2}=\frac{q}{2}

So, the new force will be

F' = k \frac{(\frac{q}{2})\cdot (\frac{3}{2}q)}{r^2}=\frac{3}{4} (k\frac{q\cdot q}{r^2})=\frac{3}{4}F

So, the force will decrease to 3/4 of its original value.

6 0
2 years ago
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