Answer:
9 kg • m/s..........................
Answer:
Explanation:
Given that,
The volume of a sample of gas measured at 27 °C is 10.0 dm.
We need to find the temperature when the volume is reduced to 9.0 dm at the same pressure.
According Charles law,
Where, T₂ is new temperature
So, the new temperature is 
.
Answer:
a) Ag(NH₃)₂⁺, Cl⁻.
b) NH₃.
c) AgCl.
Explanation:
Based on LeChatelier's law, a system in chemistry can change responding to a disturbance of concentration, temperature, etc. in order to restore a new state.
In the reaction:
AgCl(s) + 2NH₃(aq) ⇌ Ag(NH₃)₂⁺(aq) + Cl⁻(aq)
When reactants are added, the system will produce more products restoring the equilibrium and vice versa. A reactant in solid state doesn't take part in the equilibrium, thus:
a) Ag(NH₃)₂⁺, Cl⁻. The addition of products will shift the equilibrium to the left
b) NH₃. The addition of reactant will shift the equilibrium to the right.
c) As AgCl is in solid phase, will not shift the equilibrium in either direction.
Answer:
Sorry I do not know the answer but I do know its not c (pressure)
Explanation:
I took a quiz with that question and I got it wrong my other guess is air density though
