Reduction reactions are those reactions that reduce the oxidation number of a substance. Hence, the product side of the reaction must contain excess electrons. The opposite is true for oxidation reactions. When you want to determine the potential difference expressed in volts between the cathode and anode, the equation would be: E,reduction - E,oxidation.
To cancel out the electrons, the e- in the reactions must be in opposite sides. To do this, you reverse the equation with the negative E0, then replacing it with the opposite sign.
Pb(s) --> Pb2+ +2e- E0 = +0.13 V
Ag+ + e- ---> Ag E0 = +0.80 V
Adding up the E0's would yield an overall electric cell potential of +0.93 V.
Answer:
their ability to conduct heat and electricity.
Explanation:
<span>If the concentration of H⁺ ions will decrease then the concentration of OH⁺ ions will increase.</span>
Answer: 16.7 gallon
Explanation:
Given: The car can drive 30.3 miles when 1 gallon of gasoline is used.
Distance covered = 506.3 miles
Thus for 30.3 miles, the amount of gasoline used= 1 gallon
For 506.3 miles, the amount of gasoline used=
Thus the amount of gasoline used is 16.7 gallons.
The problem above can be solved using M1V1=M2V2 where M1 is the concentration of the concentrated, V1 is the volume of the concentrated solution, M2 is the concentration of the Dilute Solution, V2 is the Volume of the dilute solution. Hence,
(3.0 M)(V2)=(250 mL)(1.2M)
V2 (3.0)= 300
V2= 100 mL
Therefore, you need 100 mL of 3.0 M HCl to form a 250 mL of 1.2 M HCl.
