Answer:
I will answer in English.
Here we will use the relation
Velocity*time = distance
So:
a) velocity = 3m/s
time = 2s
Distance = 3m/s*2s = 6m
b) velocity = 2m/s
time = 3.5s
Distance = 2m/s*3.5s = 7m
c) velocity = 10m/s
time = 0.5s
Distance = 10m/s*0.5s = 5m
d) velocity = 4m/s
time = 2.5s
Distance = 4m/s*2.5s = 9m
e) velocity = 1.5m/s
time = 5s
Distance = 1.5m/s*5s = 7.5m
Average speed = (total distance covered) / (time to cover the distance)
= (50 miles) / (1.5 hours)
= (50/1.5) miles/hours
= (33 and 1/3) mph .
We don't care about all that other "data" given earlier in the question.
We only need to know the total distance covered and the time it took
to cover the distance.
Answer: 96 m/s
Explanation:
Given information
Acceleration of rocket = 24 m/s2
Distance travelled by rocket = 192 meters.
To be calculated
Velocity of rocket at 192 meters = ?
Using 2nd equation of motion, the difference of square of final and initial velocity is equal to the 2 times the product of acceleration and distance.
v2 – u2 = 2as
v2 – 0 = 2 * 24 * 192 (intial velocity is 0, so u = 0)
v2 = 9216
v =
v = 96 m/s