8(a) charges at A and B are 4q(of which its initially q and later 3q is added) and q respectively.
answer is
ANSWER:
IV, Type of dish detergent. DV, height of foam. CV, type of container, amount of water in container, temperature of water, time the container is agitated.
Explanation:
Independent variable(IV)- what you change during the experiment.
dependent variable(DV)- what you're measuring during an experiment. The dependent variable is DEPENDENT because it's results DEPEND on the independent variable at play.
Constant variables(CV)- things that do not change in order to isolate the tested variables as much as possible.
The magnitude (in N) of the electric force that one particle exerts on the other is A. F=107.6nN.
F=[(9×10^9) ×(7.10×10^-9) ×(4.42×10^-9)] /(1.62^2)
F=(282.4×10^-9)/2.6244
F=107.6×10^-9N
F=107.6nN
Experiments with electric charges have shown that two charged objects exert electrical forces on each other. The magnitude of the force is linearly proportional to the net charge of each object and inversely proportional to the square of the distance between the objects.
Coulomb's law for calculating electrostatic forces. This force arises from the interaction between two charged objects (or point charges), the magnitude of which is calculated by F = kQ1Q2r2 F = k Q 1 Q 2 r2.
Learn more about the electric field here: brainly.com/question/14372859
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Answer:3W
If it takes an amount of work W to move two q point charges from infinity to a distance d apart from each other, then how much work should it take to move three q point charges from infinity to a distance d apart from each other?
A) 2W
B) 3W
C) 4W
D) 6W
Explanation: calculating work done,W, in moving two positive q point charges from infinity to a valued distance d from each other is
W = k(+q)(+q)/ d
k is couloumb's constant
work done in moving 3 equal positive charges from infinity to a finite distance is given by
W₂=W₄=W₆=k(+q)(+q)/ d
Total work done, W' =k(+q)(+q)/ d + k(+q)(+q)/ d + k(+q)(+q)/ d
= W + W + W = 3W
Answer:
Eleven seconds.
Explanation:
Two keys are needed to solve this problem. First, the conservation of momentum: allowing you to calculate the cart's speed after the elephant jumped onto it. It holds that:
So, once loaded with an elephant, the cart was moving with a speed of 4.29m/s.
The second key is the kinematic equation for accelerated motion. There is one force acting on the cart, namely friction. The friction acts in the opposite direction to the horizontal direction of the velocity v0, its magnitude and the corresponding deceleration are:
The kinematic equation describing the decelerated motion is:
It takes 11 seconds for the comical elephant-cart system to come to a halt.
