Blank parasites can cause serious Illnesses like West Nile virus and Lyme diseases

A 500g object falls off a cliff and losers 100 J from its gravitational potential energy store. if the gravitational field stren

ludmilkaskok [199]

Answer : Height, h = 20.4 m

Explanation :

It is given that,

Mass of an object, m = 500 g = 0.5 kg

Gravitational potential energy, PE = 100 J

The Gravitational potential energy is the energy which is possessed due to the height and gravity of an object. It is given as :

PE = m g h

where,

h is the height of the cliff.

$100\ J=0.5\ kg\times 9.8\ m/s^2\times h$

h = 20.40 m

So, the height of the cliff is 20.4 m.

7 0

3 years ago

: In heavy rushIn heavy rush-hour traffic you drive in a straight line at 12 m/s for 1.5 minutes, then you have to stop for 3.5

zhuklara [117]

Guessing you want the average speed. We can multiple each speed by the time we spent going that speed, and them all together and then divide by the total time we spent in traffic to get the average speed. We spent a total of 7.5 minutes in traffic, so average speed = (12*1.5+0*3.5+15*2.5)/7.5 = 7.4 m/s

8 0

3 years ago

Which planet has a ring system made of mostly water ice?

fredd [130]

Answer:

The answer would be Saturn.

Explanation:

Hope this helps. Please mark me Brainliest

4 0

3 years ago

Read 2 more answers

Say that you are in a large room at temperature TC = 300 K. Someone gives you a pot of hot soup at a temperature of TH = 340 K.

Sliva [168]

To solve the problem it is necessary to take into account the concepts related to energy efficiency in the engines, the work done, the heat input in the systems, the exchange and loss of heat in the soupy the radius between the work done the lost heat ( efficiency).

By definition the efficiency of the heat engine is

$\epsilon = 1- \frac{T_c}{T_h}$

Where,

$T_c =$ Temperature at the room

$T_h =$ Temperature of the soup

The work done is defined as,

$dW = \epsilon(dQ_h)$

Where $Q_h$ represents the input heat and at the same time is defined as

$dQ_h =c_v (dT_h)$

Where,

$c_V =$ Specific Heat

The change at the work would be defined then as

$dW = \epsilon(dQ_h)$

$dW = \epsilon c_v (dT_h)$

$dW = (1-\frac{T_c}{T_h})c_v (dT_h)$

$W = \int dW = \int (1-\frac{T_c}{T_h})c_v (dT_h)$

$W = c_v (T_h-T_c)-c_v T_c ln(\frac{T_h}{T_c})$

On the other hand we have that the heat lost by the soup is equal to

$dQ_h =c_v (dT_h)$

$Q_h =c_v (T_h-T_c)$

The ratio between both would be,

$\frac{W}{Q_h} = \frac{c_v (T_h-T_c)-c_v T_c ln(\frac{T_h}{T_c})}{c_v (T_h-T_c)}$

$\frac{W}{Q_h} = \frac{1+ln(\frac{T_h}{T_c})}{1-\frac{T_h}{T_c}}$

Replacing with our values we have,

$\frac{W}{Q_h} = 1+\frac{ln(\frac{340K}{300K})}{1-\frac{340K}{300K}}$

$\frac{W}{Q_h} = 0.0613$

Therefore the fraction of heat lost by the soup that can be turned into useable work by the engine is 0.0613.

5 0

3 years ago

Which combination of cell increases both electric current and electromotive force?

inn [45]

Answer:

In parallel combination, the cells are connected in such a way that the potential difference of the circuit is same as the cells used in the circuit but the time of current flowing increases

3 0

1 year ago